The function increases in the interval (-∞, -3) and the function also increases in the interval (-1,∞) .
The given function is of the form
f(x) = x³ + 6x² + 8x
Now we take the first differentiation of the function
f'(x) = 2x² + 12x + 8
f'(x) = 2 (x² + 6x + 9) -10
f'(x) = 2(x+3)² - 10
Therefore at x = -3 , f'(x) = -10.
Hence the function is increasing in the interval of (-∞, -3)
Again f'(x) = 2x² + 12x + 8 , so after first differentiation we get :
That the function is also increasing in the interval (-1,∞)
Now for the interval (-4,-2), we can say that the graph of the function is positive as the y value increases and then decreases but all y values are positive as illustrated in the graph.
In the interval (0,∞) the function is strictly increasing and has positive values only.
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Answer:
10000
Step-by-step explanation:
85000 is nearest to 10000
Answer:
lst1 = [4, 3, 2, 6, 2]
lst2 = [1, 2, 4]
new_lst = []
for i in lst1:
if i in lst2:
new_lst.append(i)
new_lst.sort()
print(new_lst)
Step-by-step explanation:
The code is written in python.
lst1 = [4, 3, 2, 6, 2]
The variable lst1 represent a list of integers.
lst2 = [1, 2, 4]
The variable lst2 represent a list of integers.
new_lst = []
An empty variable is created new_lst and it is used to store the values of lst1 that is in lst2.
for i in lst1:
The code loop through integers in lst1.
if i in lst2:
This code means if any of the value in lst1 is in lst2.
new_lst.append(i)
This code put the same values found in lst1 and lst2 in a new list(new_lst)
new_lst.sort()
We sort the value of the new list from the smallest to the biggest.
print(new_lst)
The new list is displayed
Answer:
.vfncjhfbntbdnfkurbtncivt mckcudv dmdj + .vfncjhfbntbdnfkurbtncivt mckcudv dmdj = .vfncjhfbntbdnfkurbtncivt mckcudv dmdj.vfncjhfbntbdnfkurbtncivt mckcudv dmdj
Step-by-step explanation:
Answer:
hey hey hey hey hye hye heyr32klq,adm.
Step-by-step explanation:
