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Goshia [24]
3 years ago
11

Which atom loses 2 electrons while forming an ion?

Chemistry
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

it would be a cation ... i believe

Explanation:

To become a cation, a positively charged ion, an atom would have to lose at least two electrons  

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Which statement is always true about a reversible chemical reaction?
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Answer:

<em>It is a chemical reaction in which the reactants form products and products react together to give reactants back. That means reversible reactions can go in both directions forward as well as backward direction.</em>

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3 years ago
How many liters of Cl2 gas will you have if you are using 63 g of Na?
ELEN [110]

Answer:

You will have 19.9L of Cl2

Explanation:

We can solve this question using:

PV = nRT; V = nRT/P

<em>Where V is the volume of the gas</em>

<em>n the moles of Cl2</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is 273.15K assuming STP conditions</em>

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The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:

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Replacing:

V = 0.8885mol*0.082atmL/molK*273.15K/1atm

V = You will have 19.9L of Cl2

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2. What is the mass of 5.3 moles of CaCl2?
Tanya [424]

Answer:

590 g CaCl₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

5.3 mol CaCl₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of CaCl₂ - 40.08 + 2(35.45) = 110.98 g/mol

<u>Step 3: Convert</u>

<u />5.3 \ mol \ CaCl_2(\frac{110.98 \ g \ CaCl_2}{1 \ mol \ CaCl_2} ) = 588.194 g CaCl₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

588.194 g CaCl₂ ≈ 590 g CaCl₂

5 0
3 years ago
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