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Goshia [24]
3 years ago
11

Which atom loses 2 electrons while forming an ion?

Chemistry
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

it would be a cation ... i believe

Explanation:

To become a cation, a positively charged ion, an atom would have to lose at least two electrons  

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Polymerization because monomers are joined to form a larger molecule. These units are linked together with different types of bonds depending on the class of the molecule such as carbohydrates, lipids, or proteins.

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Steps of photosynthesis:
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Chlorophyll absorbs light energy, ATP molecules form, sugar molecules form. I'm pretty sure this is correct, but if it is not I'm sorry...

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Can someone tell me if these are right? I am supposed to be decoding this for my escape room but it seems to be wrong.
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3 years ago
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
4 years ago
21. A piece of metal with a a mass of 15.2 g is heated from 17°C to 42°C. In the process it absorbs 1362 J of
Sholpan [36]

Answer:

3.58J/g°C is the specific heat of the metal

Explanation:

The specific heat of a material is defined as the energy that 1g of the material absorbs and produce the increasing in temperature in 1°C. The equation is:

Q = S*ΔT*m

<em>Where Q is energy = 1362J</em>

<em>S is specific heat of the material</em>

<em>ΔT is change in temperature = 42°C - 17°C = 25°C</em>

<em>And m is the mass of the material = 15.2g</em>

Replacing:

S = Q / ΔT*m

S = 1362J / 25°C*15.2g

<h3>3.58J/g°C is the specific heat of the metal</h3>
4 0
3 years ago
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