If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
ss reactant will be left over when the reaction is complete? Be sure to write out the balanced equation for this reaction and to show all of your work.
2Ca + O2 = 2CaO First, determine which is the excess reactant 72.5 g Ca (1 mol) =1.8089725036 (40.078 g)
65 g O2 (1 mol) =2.0313769611 (15.999g × 2) Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry 72.5 g Ca (1 mol Ca) (1 mol O2) (40.078 g Ca)(2 mol Ca)(31.998g O2)
