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Nataly_w [17]
3 years ago
14

If 8 g of ammonium hydroxide is completely decomposed by the reaction below in a closed container with a total volume of 5.oo L

and at 25 degrees C, what will be the partial pressure of the amonia gas liberated, in atmospheres? Assume the volume of the liquid is negligible.
NH4OH(aq)=H2O(1)+NH3(g)
Chemistry
1 answer:
Alla [95]3 years ago
7 0

Answer:

1 atm

Explanation:

Step 1: Write the balanced equation

NH₄OH(aq) ⇒ H₂O(l) + NH₃(g)

Step 2: Calculate the moles corresponding to 8 g of NH₄OH

The molar mass of NH₄OH is 35.04 g/mol.

8 g × 1 mol/35.04 g = 0.2 mol

Step 3: Calculate the moles of NH₃ formed from 0.2 moles of NH₄OH

The molar ratio of NH₄OH to NH₃ is 1:1. The moles of NH₃ formed are 1/1 × 0.2 mol = 0.2 mol

Step 4: Calculate the pressure of 0.2 moles of NH₃ in a container of 5.00 L at 25 °C (298 K)

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 0.2 mol × 0.0821 atm.L/mol.K × 298 K / 5.00 L

P = 1 atm

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The Law of Conservation of Mass states that matter is not created nor destroyed.

Based on this, we can use some addition to find the answer.

3.00 + 1.40 = 4.40 g

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4 0
3 years ago
A chemist fills a reaction vessel with mercurous chloride solid, mercury (I) aqueous solution, and chloride aqueous solution at
makvit [3.9K]

Answer:

ΔG° = -533.64 kJ

Explanation:

Let's consider the following reaction.

Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)

The standard Gibbs free energy (ΔG°) can be calculated using the following expression:

ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)

where,

ni are the moles of reactants and products

ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products

ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)

ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)

ΔG° = -533.64 kJ

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What is the mass of 25 Liters of nitrogen dioxide gas?
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Explanation:

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True or false. adding more neutrons to a neutrally charged atom will not change the charge
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What mass of oxygen contains the same number of molecules as 42g of nitrogen?
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Answer:

Given: 42 g of N2

Solve for O2 mass that contains the same number of molecules to 42 g of N2.

Solve for the number of moles in 42 g of N2

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Solve for mass of 1 mole of oxygen

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Solve for the mass of 1.5 moles of oxygen

mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles

mass of 1.5 moles of O2 = 48 g

So 48 g of O2 contains the same number of molecules as 42 g of N2

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3 years ago
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