All categories

2 years ago

6x - 8 ≤ 184 i need answer for test corrections

Mathematics

1 answer:

jekas [21]2 years ago

5 0

I hope this helps.....

Explanation:
I took this in 9th grade so I know how to do this kind of stuff

You might be interested in

Saving and Spending In this open response, you will be managing a checkbook and savings account.

user100 [1]

Answer:

laviña and the two girl had been on my mind

Step-by-step explanation:

laviña and the two girl had been on my mind that you add me I need to renounce I'm poor you ty

7 0

2 years ago

John goes running every morning. He can run 3 miles in 1 hour. How many miles would he be able to run in 1 and ½ hours?

sp2606 [1]

Answer:

4.5 or 4 1/2 miles

Step-by-step explanation:

$\dfrac{3\text{ miles}}{\text{hour}}\cdot 1.5 \text{ hours}= 3\cdot 1.5=4.5$

Hope this helps!

5 0

3 years ago

Please show work and correct answers ONLY!

amm1812

April 11 : 3 hours 15 minutes

April 12 : 3 hours

April 13 : 4 hours 30 minutes

April 14 : 5 hours 15 minutes

April 15 : 2 hours 45 minutes

total : 18 hours 45 minutes

10.50 * 18.75 = $196.875

answer: $196.88

45 1/4-> 45.25 * .5 = 22.625 = 22 5/8

gusset plate :

5 3/4 -> 5.75 * .5 = 2.875 = 2 7/8

3 1/2 -> 3.5 * .5 = 1.75 = 1 3/4

47 1/4 -> 47.25 * .5 = 23.625 = 23 5/8

2 * .5 = 1

5 0

2 years ago

What is the measurement of the third angle of a triangle if the first two angles measure 63 degrees and 87 degrees?

kherson [118]

Answer:

Step-by-step explanation:

trey

7 0

2 years ago

Read 2 more answers

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago