Depth=15
x=(height(h)*width(w)*hypotenuse(y))/2
x=(3*4*5)/2=(60/2)=30
y=(x(x-h)(x-w)(x-y))^(1/2)
f=(-h^4+2(hw)^2+2(wy)^2-w^4+2(hy)^2-y^4)^(1/2)
f=(-3^4+2(3*4)^2+2(4*5)^2-4^4+2(3*5)^2-5^4)^(1/2)
f=576^(1/2)
f=24
Surface Area= 2f(.5)+(h+w+y)*depth
192=depth*(3+4+5)+24(.5)
180=(3+4+5)*depth
180=(12)(depth)
15=depth
Answer:
x = 20
Step-by-step explanation:
The two indicated angles are vertical angles and vertical angles are equal
3x+50 = 6x-10
Subtract 3x from each side
3x-3x+50 = 6x-10-3x
50 = 3x-10
Add 10 to each side
50+10 = 3x-10+10
60 = 3x
Divide each side by 3
60/3 = 3x/3
20 =x
A. you plug in to a calculator, which will give 1840.986 so you need to round up to 1840.99. if you truncate it to .98 then he won't reach 2000 in 3 years
b. for this one if you look at the equation given to find the principle it is principle = result (1+rate) ^ -time
if you re arrange this you get result=principle (1+rate)^time
so result = 1840.99(1.028)^5
= 2113.57
Since the stadium is 6 mi from the practice field which is itself 1 mi from the house, it can either be (1+6)=7 mi North or (1-6)=-5 -> 5 mi South depending on the North/South direction.
the answer is thus A
X+
=12
5x=36
x=7.2
So, the triangular entrance to the tent is
7.2 feet tall and
4.8 feet wide
