Hey there,
6x + 5 (x-2)
6x + 5x - 10
11x - 10
3x - 5 - x + 9
3x - x - 5 + 9
2x + 4
3a + 5 - 8a + 1
3 (-1) + 5 - 8(-1) + 1
-3 + 5 + 8 + 1
11
Hope this helps :))
<em>~Top♥</em>
Answer: The area of the enclosure is 1,029 square meters
Step-by-step explanation: The first thing is to use the unit of measurement required by the question, and to do this we need to convert what we have to what is required.
If the scale of the diagram is given as every 4cm represents 7m, that means, every unit of the actual measurement would be given as
(X/4) x 7
For the length of the enclosure, we can determine that as follows;
Length = (28/4) x 7
Length = 7 x 7
Length = 49m
And for the width,
Width = (12/4) x 7
Width = 3 x 7
Width = 21m
Therefore, the area is calculated as,
Area = L x W
Area = 49 x 21
Area = 1029 m²
Answer:
df
Step-by-step explanation:
Let

be the point on the ground to with the 18 foot guy is anchored and

the point on the ground to with the 21 foot guy is anchored.
We can conclude that the <span>the two wires at the points where they are anchored are
21 feet apart. Check the procedures in the picture attached.</span>