Answer:28
Step-by-step explanation:
Answer:
Part 1) ![y=2x+3](https://tex.z-dn.net/?f=y%3D2x%2B3)
Part 2) The equation satisfy the set of coordinates (see the explanation)
Step-by-step explanation:
step 1
Find the linear equation
The rule for the linear equation states that y is three more than twice x.
so
The variable y is equal to the number 2 multiplied by x plus the number 3
![y=2x+3](https://tex.z-dn.net/?f=y%3D2x%2B3)
step 2
Prove that the equation satisfies the set of coordinates
substitute the value of x and the value of y in the linear equation and then compare the results
a) (-1, 1)
![1=2(-1)+3](https://tex.z-dn.net/?f=1%3D2%28-1%29%2B3)
----> is true
so
The equation satisfy the ordered pair
b) (0, 3)
![3=2(0)+3](https://tex.z-dn.net/?f=3%3D2%280%29%2B3)
----> is true
so
The equation satisfy the ordered pair
c) (-1/3,7/3)
![7/3=2(-1/3)+3](https://tex.z-dn.net/?f=7%2F3%3D2%28-1%2F3%29%2B3)
----> is true
so
The equation satisfy the ordered pair
therefore
The equation satisfy the set of coordinates
Answer:
The scale factor is 1/2 or .5
Step-by-step explanation:
Triangle XYZ scales down by 1/2 to form the new XYZ triangle
For example: on the left side, X is (6,4) and on the right side, X is (3,2)... it's cut in half meaning the scale factor is 1/2 or .5
Hopefully this isn't confusing and it helps... :)
Answer:
(1) 23.55mm³
(2) 340.17in³
Step-by-step explanation:
Volume of a cone is: ![V=\frac{1}{3} \pi r^2h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2h)
'r' - radius
'h' - height
<h3>Cone 1:</h3>
The height of Cone 1 is 10 mm. The Diameter of Cone 1 is 3mm.
Radius is half the Diameter.
![3/2=1.5](https://tex.z-dn.net/?f=3%2F2%3D1.5)
The radius is 1.5 mm.
![\text {Using 3.14 as pi: }\\V=(1/3)3.14*1.5^2*10\\V=(1/3)3.14*2.25*10\\V=(1/3)70.65\\\boxed{V=23.55}](https://tex.z-dn.net/?f=%5Ctext%20%7BUsing%203.14%20as%20pi%3A%20%7D%5C%5CV%3D%281%2F3%293.14%2A1.5%5E2%2A10%5C%5CV%3D%281%2F3%293.14%2A2.25%2A10%5C%5CV%3D%281%2F3%2970.65%5C%5C%5Cboxed%7BV%3D23.55%7D)
The volume of Cone 1 should be about 23.55mm³.
<h3>Cone 2:</h3>
The height of Cone 2 is 13 in. The Radius of Cone 2 is 5 in.
Using 3.14 as pi:
![V=(1/3)3.14*5^2*13\\V=(1/3)3.14*25*13\\V=(1/3)1020.5\\\boxed {V=340.166666667}](https://tex.z-dn.net/?f=V%3D%281%2F3%293.14%2A5%5E2%2A13%5C%5CV%3D%281%2F3%293.14%2A25%2A13%5C%5CV%3D%281%2F3%291020.5%5C%5C%5Cboxed%20%7BV%3D340.166666667%7D)
340.166666667 ≈ 340.17
The volume of Cone 2 should be about 340.17in³.
Answer:
6√2
Step-by-step explanation:
use pythagorean theorem
x=√(6^2+6^2)
or, x=√(36+36)
therefore,
x=6√2