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Hatshy [7]
3 years ago
6

Solve for z -0.25z= -1.25

Mathematics
2 answers:
natita [175]3 years ago
8 0

Answer:

<h3>\boxed{ \bold{ \purple{z = 5}}}</h3>

Step-by-step explanation:

\mathsf{ - 0.25z =  - 1.25}

Divide both sides of the equation by -0.25

\mathsf{ \frac{ - 0.25z}{ - 0.25}  =  \frac{ - 1.25}{ - 0.25} }

Calculate

\mathsf{z = 5}

Hope I helped !

Best regards!

GarryVolchara [31]3 years ago
6 0

Answer:

<h2>z = 5</h2>

Step-by-step explanation:

-0.25z= -1.25

Convert the decimals to improper fractions

That's

<h3>- 1.25 =  -  \frac{5}{4}</h3><h3>- 0.25 =  -  \frac{1}{4}</h3>

So we have

<h3>-  \frac{1}{4} z =  -  \frac{5}{4}</h3>

Multiply through by 4

We have

- z = - 5

Divide both sides by - 1

the final answer is

<h3>z = 5</h3>

Hope this helps you

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Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

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So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

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                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

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