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Hatshy [7]
3 years ago
6

Solve for z -0.25z= -1.25

Mathematics
2 answers:
natita [175]3 years ago
8 0

Answer:

<h3>\boxed{ \bold{ \purple{z = 5}}}</h3>

Step-by-step explanation:

\mathsf{ - 0.25z =  - 1.25}

Divide both sides of the equation by -0.25

\mathsf{ \frac{ - 0.25z}{ - 0.25}  =  \frac{ - 1.25}{ - 0.25} }

Calculate

\mathsf{z = 5}

Hope I helped !

Best regards!

GarryVolchara [31]3 years ago
6 0

Answer:

<h2>z = 5</h2>

Step-by-step explanation:

-0.25z= -1.25

Convert the decimals to improper fractions

That's

<h3>- 1.25 =  -  \frac{5}{4}</h3><h3>- 0.25 =  -  \frac{1}{4}</h3>

So we have

<h3>-  \frac{1}{4} z =  -  \frac{5}{4}</h3>

Multiply through by 4

We have

- z = - 5

Divide both sides by - 1

the final answer is

<h3>z = 5</h3>

Hope this helps you

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What is the first derivative of r with respect to t (i.e., differentiate r with respect to t)? r = 5/(t2)Note: Use ^ to show exp
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Answer:

The first derivative of r(t) = 5\cdot t^{-2} (r(t)=5*t^{-2}) with respect to t is r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3}).

Step-by-step explanation:

Let be r(t) = \frac{5}{t^{2}}, which can be rewritten as r(t) = 5\cdot t^{-2}. The rule of differentiation for a potential function multiplied by a constant is:

\frac{d}{dt}(c \cdot t^{n}) = n\cdot c \cdot t^{n-1}, \forall \,n\neq 0

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