Answer:
Given that a beetle has the pattern, 0.098 is the probability that it belongs to the rare subspecies
Step-by-step explanation:
Probability of having a pattern in rare subspecies
Percentage of rare subspecies = 1 % = 0.01
Probability of a beetle with pattern belonging to rare subspecies is
Answer:
- f⁻¹(x) = (x + 1) / (x - 2)
- f⁻¹(1 ) = - 2
Step-by-step explanation:
<u>Given function:</u>
- f(x) = (2x + 1) / (x - 1)
<u>Find its inverse, substitute x with y and f(x) with x, solve for y:</u>
- x = (2y + 1) / (y - 1)
- x(y - 1) = 2y + 1
- xy - x = 2y + 1
- xy - 2y = x + 1
- y(x - 2) = x + 1
- y = (x + 1) / (x - 2)
<u>Substitute y with f⁻¹(x):</u>
- f⁻¹(x) = (x + 1) / (x - 2)
<u>Find f⁻¹(1 ):</u>
- f⁻¹(1 ) = ( 1 + 1) / (1 - 2) = 2 / - 1 = - 2
Answer:
16/25
Step-by-step explanation:
length of screen B=44*(5/4)=55cm
and its width=32*(5/4)=40cm
so, screen B had dimensions 55cm by 40 cm
screen A area=44*32 cm sqr
screen B area=55*40 cm sqr
so, model A screen area/model B screen area
=(44*32)/(55*40)
=16/25