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2 years ago

A rectangular prism has a length of 10m, a height of 2m, and a width of 5m. What is its volume, in cubic m?

Mathematics

2 answers:

Veseljchak [2.6K]2 years ago

8 0

50 meters cubed because you have to multiple (2()5)(10)

ArbitrLikvidat [17]2 years ago

8 0

Volume = lwh
10•2•5
20•5
100

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I came up the answer as 57. I will attach my note, can you check?

ololo11 [35]

BC=19

Explanation

Step 1

ABE

triangle ABE is rigth triangle, then let

$\begin{gathered} Angle=60 \\ adjacentside=BE \\ opposit\text{ side(the one in front of the angle)= AB=}\frac{19\sqrt[]{6}}{4} \end{gathered}$

so, we need a function that relates, angle, adjancent side and opposite side

$\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}$

replace

$\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan 60=\frac{AB}{\text{BE}} \\ \text{cross multiply} \\ \text{BE}\cdot\tan \text{ 60=AB} \\ \text{divide both sides by tan 60} \\ \frac{\text{BE}\cdot\tan\text{ 60}}{\tan\text{ 60}}=\frac{\text{AB}}{\tan\text{ 60}} \\ BE=\frac{\text{AB}}{\tan\text{ 60}} \\ \text{if AB=}\frac{19\sqrt[]{6}}{4} \\ BE=\frac{\frac{19\sqrt[]{6}}{4}}{\sqrt[]{3}} \\ BE=\frac{19\sqrt[]{6}}{4\sqrt[]{3}} \end{gathered}$

Step 2

BED

again, we have a rigth triangle,then let

$\begin{gathered} \text{Hypotenuse}=BD \\ \text{adjacent side= BE=6.71} \\ \text{angle}=\text{ 45} \end{gathered}$

so, we need a function that relates; angle, hypotenuse and adjacent side

$\cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}$

replace.

$\begin{gathered} \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \cos 45=\frac{6.71}{\text{BD}} \\ BD=\frac{6.71}{\cos \text{ 45}} \\ BD=\frac{\frac{19\sqrt[]{6}}{4\sqrt[]{3}}}{\frac{\sqrt[]{2}}{2}} \\ BD=\frac{38\sqrt[]{6}}{4\sqrt[]{6}} \\ BD=\frac{38}{4} \end{gathered}$

Step 3

finally BDE

let

angle=30

opposite side= BD

use sin function

$\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{replace} \\ \sin \text{ 30=}\frac{BD}{BC} \\ BC\cdot\sin 30=BD \\ BC=\frac{BD}{\sin \text{ 30}} \\ BC=\frac{\frac{38}{4}}{\frac{1}{2}} \\ BC=\frac{76}{4}=19 \\ BC=19 \end{gathered}$

so, the answer is 19

I hop

4 0

1 year ago

Gavin's dog had a litter of puppies. All of the puppies in this litter were either yellow or black. If there was one less black

mezya [45]

Answer:

Total number of puppies in the litter = 11

Step-by-step explanation:

Let the number of yellow puppies in the litter = y

And the number of black puppies in the litter = b

If there was one less black puppy, ratio of yellow to black puppies = $\frac{2}{3}$

$\frac{y}{b-1}=\frac{2}{3}$

2(b - 1) = 3y

3y - 2b = -2 -----(1)

If there was one more black puppy, ratio of yellow puppies to black puppies = $\frac{1}{2}$

$\frac{y}{b+1}=\frac{1}{2}$

2y = b + 1

2y - b = 1 -------(2)

Equation (1) - 2× equation (2)

(3y - 2b) - 2(2y - b) = -2 - 2

3y - 4y - 2b + 2b = -4

y = 4

From equation (1),

3×4 - 2b = -2

12 - 2b = -2

-2b = -14

b = 7

Total number of puppies in the litter = 7 + 4 = 11

4 0

3 years ago

What is the corrct answer

Mademuasel [1]

D is the right answer

4 0

3 years ago

Jlenok [28]

Answer:

False

Step-by-step explanation:

3 0

3 years ago

A cylinder and a cone have the same volume. The cylinder has radius x and height y. The cone has radius 2x. Find the height of t

weqwewe [10]

V(cylinder)=πR²H
Radius of the cylinder R=x, height of the cylinder H=y.
We can write for the cylinder
V(cylinder)=πx²y

V(cone) =(1/3)πr²h
Radius of the cone r=2x.
We can write for the cone
V(cone)= (1/3)π(2x)²h=(1/3)π *4*x²h

V(cylinder) =V(cone)
πx²y=(1/3)π *4*x²h
y=(4/3)*h
h=(3/4)*y

7 0

3 years ago