Answer:
d
Step-by-step explanation:
base² + Altitude² = Hypotenuse²
x² + 9² = 13²
x² + 81 = 169
x² = 169 - 81
x² = 88
x = 

The correct answer is option D which is p ³+ 2; when p = 3 the number of plants is 29.
The complete question is given below:-
liana cubed the number of flowering plants in her garden, then added 2 vegetable plants. Let p represent the original number of plants in her garden. Which shows an expression to represent the total number of plants in her garden and the total number of plants if p = 3? 3 p minus 2; when p = 3 the number of plants is 7 3 p + 2; when p = 3 the number of plants is 11 p cubed minus 2; when p = 3 the number of plants is 25 p cubed + 2; when p = 3 the number of plants is 29
<h3 /><h3>
What is an expression?</h3>
Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
The given expression is liana cubed the number of flowering plants in her garden, then added 2 vegetable plants.
If she cubed the number of the plants will be:- P³
Now she added two vegetable plants:- 2
Then the equation will be:- p³ + 2. Now we will put the value of p = 3 in the equation.
Total number of the plants = ( 3 )³ + 2 = 27 + 2 = 29
Therefore the correct answer is option D which is p³+ 2; when p = 3 the number of plants is 29.
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Answer:
June has 7 green and 28 blue marbles
Step-by-step explanation:
b + g = 35
b = 4g
Use substitution method to solve them simultaneously
4g + g = 35
5g = 35
g = 7
b = 4g = 4(7) = 28
b = 28, g = 7
She has 7 green and 28 blue marbles
First, multiply 30 with 25
30 x 25 = Area
Area = 750 square yards
one bag gives you 100 square yards
Divide the two numbers
750/100 = 7.5
Since you cannot buy half a bag, you must round up
8 bags is needed
hope this helps
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
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