The answer is 54 square units.
let the vertex in quadrant I be (x,y)
<span>then the vertex in quadratnt II is (-x,y) </span>
<span>base of the rectangle = 2x </span>
<span>height of the rectangle = y </span>
<span>Area = xy </span>
<span>= x(27 - x</span>²<span>) </span>
<span>= -x</span>³<span> + 27x </span>
<span>d(area)/dx = 3x</span>²<span> - 27 </span><span>= 0 for a maximum of area </span>
<span>3x</span>²<span> = 3 x 3</span>² = <span>27 </span>
<span>x</span>²<span> = 9 </span>
<span>x = ±3 </span>
<span>y = 27-9 = 18 </span>
So, the largest area = 3 x 18 = 54 square units
Hello
11 cm, 25 cm, 15 cm
if you add the lengths of two sides of the triangle, it must be greater than the length of the third side
therefore, the only possible lengths are 11 cm, 25 cm, 15 cm
Have a nice day
Answer:
<em>Expected Payoff ⇒ $ 1.50 ; Type in 1.50</em>
Step-by-step explanation:
Considering that 1 out of the 100 tickets will have a probability of winning a 150 dollar prize, take a proportionality into account;
<em>Thus, Solution ; Expected Payoff ⇒ $ 1.50</em>