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Lady bird [3.3K]
4 years ago
12

What is the equation for a line that passes through the points (5,-3) and (-10,12)?

Mathematics
2 answers:
Gala2k [10]4 years ago
7 0

Answer:

y = -x + 2

Step-by-step explanation:

First, find the slope.

12 - (-3) / -10 - 5

15/-5

-1

The slope is -1.

Our equation will be y = -1x + b

Insert on the x,y corrdinates given.

12=-1(-10) + b

12=10 + b

2 = b

Now that we know b,

the equation is

y = -x + 2

LekaFEV [45]4 years ago
5 0

Answer: y = -x + 2

Step-by-step explanation:

When x=0, y = 2

When y=0, x = 2

Hope this helps!

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3 years ago
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Step-by-step explanation:

Oof, all 6?  That's not fun.  

I'm going to show you one for the first bunch, (4-12) and hopefully you can get the rest.  If not let me know and I can more carefully work you through some others on here.

4)  So first we need the angle.  How do we find that?  Well, we know it's somewhere between 270 and 360 degrees (or 3pi/2 and 2pi radians) since it's in the fourth quadrant.    The method to finding the angle is ifferent for each quadrant, but it's nice to know around where you'll get.  Anyway,, if we take 360 and subtract that little space  that is unlabeled  we will know  the rest.    Hopefully that makes sense, but let me know if not, it's important to understand.  Maybe think of what happens if you add the two together, you get around the whole circle then.  

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s = arcsin(3/5) (you can find 5 pretty easily but let me know if you don't see it.)

You may think to use -3 instead of 3, and  it wouldn't be a huge mistake, it will just give you the negative version of what we want.  

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3 0
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