The answer would be 483,972 miles = 55
The answer is 33. First do 3 times 5, 15, then do that -2. 13. 13 plus 4 times 5 is 33 :)
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out during work were 244 and those that never felt stressed out were 495.
Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B)
P(B) is the probability of having a male.
P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
= 244/739
= 0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
Answer: x(t) = 5cm*cos(t*pi/2s)
Step-by-step explanation:
This is a sinusoidal equation, so we can write this as:
x(t) = A*cos(c*t + p) + B
where B is the axis around the movement, as the resting position is x = 0, we have B = 0
so x(t) = A*cos(c*t + p)
A is the amplitude of the oscilation, c is the frequency and p is a phase.
We know that when t = 0s, we have x(2s) = 5cm
if this is the maximum displacement, then knowing that the maximum of the cosine is cos(0) = 1
then we must have that p = 0
x(0s) = A*cos(0) = 5cm
then we have A = 5cm
Now, when t = 2s, we have:
x(2s) = 5cm*cos(2s*c) = -5cm
then 2s*c is the minimum of the cos(x) function, this is:
cos(pi) = -1
then 2s*c = pi
c = pi/2s.
then our function is:
x(t) = 5cm*cos(t*pi/2s)
