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Lesechka [4]
3 years ago
12

What is the area of this figure? Enter your answer in the box

Mathematics
1 answer:
mezya [45]3 years ago
3 0
Area of square is a^2
5^2 =25
area of triangle is base x height divide by 2
5x4=20
20 divide by 2 is 10
add them together
25+10=35
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How many solutions does the system of equations below have?<br> y = –7x − 9<br> y = 23x − 89
Vlad1618 [11]

Answer:  infinitely many solutions

Step-by-step explanation: A system of two equations can be classified as follows:

If the slopes are the same but the y-intercepts are different, the system has no solution.

If the slopes are different, the system has one solution.

If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.

5 0
2 years ago
How you write a verbal expression for the algebraic expression -3s.​
ira [324]

Step-by-step explanation:

Negative three times a certain number

3 0
3 years ago
Kay's mother taught her how to make handmade ornaments to sell at a craft fair. Kay rented a table at the fair for $30 and set u
leva [86]

Answer:

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5 0
3 years ago
A woman made $45,000 during the first year of her new job at city hall. Each year she received a 10% raise. Find her total earni
kati45 [8]
Equation: 45000(1+.1)^6

Answer: 79720.25

Explanation:

This is a prime example of a Compound Interest Formula based question. Due to the fact the question states that the woman is getting a raise every year, we add one rather than subtracting one. Next we convert the 10% into a decimal form into 0.1 and from there since the time is all the same we wouldn’t need to divide anything out so we raise the equation to the sixth power and our final answer is $79720.25
5 0
4 years ago
Given line LM and point R that lies on line LM, identify the following ratios given that point R lies a/b of the way along line
gavmur [86]

Answer:

See explanation

Step-by-step explanation:

If point R lies \frac{a}{b} of the way along line LM, closer to L than M, then

LR=ax\\ \\LM=bx

Find all needed ratios:

1. \dfrac{LR}{LM}=\dfrac{ax}{bx}=\dfrac{a}{b}

2. By segment addition postulate,

LR+RM=LM\\ \\RM=bx-ax=(b-a)x,

so

\dfrac{RM}{LM}=\dfrac{(b-a)x}{ax}=\dfrac{b-a}{a}

3. RL=LR=ax\\ \\RM=(b-a)x,

then

\dfrac{RL}{RM}=\dfrac{ax}{(b-a)x}=\dfrac{a}{b-a}

5 0
4 years ago
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