Ask question

Ask question

All categories

2 years ago

15

How are independent and dependent variables different

1 answer:

alisha [4.7K]2 years ago

6 0

Answer:

Step-by-step explanation:

The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable. The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

You might be interested in

Find the area, help please

mafiozo [28]

Answer:

Area- 22.5

Step-by-step explanation:

To find the area in a triangle you will want to multiple the base with the height then divide it by two. in this photo you have two options 9X5/2 or 7.5X6/2

remember- a= 1/2 b X h

4 0

2 years ago

Need help asap!!!

Rama09 [41]

Answer:

B.) 45

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the area of the shaded region round to the nearest tenth .

Leviafan [203]

200.7 I hope this is the answer

4 0

3 years ago

Read 2 more answers

How much tip should you leave if you want to tip 25% at PF Chang on a $37.99 bill ??

Naddik [55]

Answer:

Step-by-step explanation:

37.99 * 25%= 9.497 or $9.50 tip

3 0

2 years ago

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago