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3 years ago

Is one flag a translation image of the other, or a rotation image? EXPLAIN

Mathematics

2 answers:

S_A_V [24]3 years ago

6 0

The flags are a translation. Both flags are located at different origins, so it couldn't be a rotation. Both flags have the colors in the same place ( black on the bottom, white on the top) so one flag was moved up or down from the other flag, which is a translation.

kicyunya [14]3 years ago

4 0

Answer:

Step-by-step explanation:

The flags are a translation. Both flags are located at different origins.The object is not altered in any other way. It is not rotated, reflected or re-sized .In translation, every point of the object must move in the same direction and the same distance.

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Can someone please help me with all of these problems. They are a ton of them and they are due tomorrow. PLEASE AND THANK YOU

Masteriza [31]

15. $\frac{x}{5} - g = a$

Add "g" on both sides

$\frac{x}{5} = a +g$

Multiply 5 on both sides to get x by itself

x = 5(a + g)

x = 5a + 5g

18. a = 3n + 1

Subtract 1 on both sides

a - 1 = 3n

Divide 3 on both sides to get n by itself

$\frac{a - 1}{3} = \frac{a}{3} -\frac{1}{3}$ = n

21. M = T - R

Add "R" on both sides to get "T" by itself

M + R = T

24. 5p + 9c = p

Subtract "5p" on both sides

9c = p - 5p

9c = -4p

Divide 9 on both sides to get "c" by itself

c = $\frac{-4p}{9}$ or c = $\frac{-4}{9} p$

27. 4y + 3x = 5

Subtract "4y" on both sides

3x = 5 - 4y

Divide 3 on both sides to get "x" by itself

x = $\frac{5-4y}{3}$

x = $\frac{5}{3} -\frac{4y}{3}$

7 0

3 years ago

The following proof shows an equivalent system of equations created from another system of equations. Fill in the missing reason

Nookie1986 [14]

Answer:

<h2>A.Multiplication Property of Equality</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+2y=14\\-x+y=5&\text{\underline{multiply both sides by 2}}\end{array}\right\\\\\boxed{\underline{+\left\{\begin{array}{ccc}2x+2y=14\\-2x+2y=10\end{array}\right}}\qquad\text{add both sides of the equations}\\.\qquad\qquad4y=24\qquad\text{divide both sides by 4}\\.\qquad\qquad y=6\\\\\text{put the value of y to the second equation:}\\\\-x+6=5\qquad\text{subtract 6 from both sides}\\-x=-1\qquad\text{change the signs}\\x=1$