Let's factorise it :
Using Distributive property we get :
⠀
Therefore,
A manufacturer makes two types of handmade fancy paper bags. Type A and Type B. Two designers a cutter and a finisher need to wo
rk on both kinds of bags. A type A bag requires 2 hours of the cutters time and 3 hours of the finishers time. A type B bag requires 3 hours of the cutters time and 1 hour of the finishers time. Each month the cutter is available for 108 hours and the finisher is available 78 hours. The manufacturer gets a profit of $12 for each bag of type A and $9 for each bag of type B. Identify the number of bags for each type to be manufactured to obtain the maximum profit.
1 answer:
Answer:
- 18 Type A bags
- 24 Type B bags
Step-by-step explanation:
The graph shows the constraints and the boundaries of the feasible region. The maximum profit will be had with the manufacture of 18 Type A bags and 24 Type B bags.
__
The inequality describing the constraint on cutter hours is ...
2a +3b ≤ 108
The inequality describing the constraint on finisher hours is ...
3a +1b ≤ 78
The boundary lines of the solution regions of these inequalities intersect at ...
(a, b) = (18, 24)
The profit function is such that it doesn't pay to make all of one type or the other bags. The most profit is had for the mix ...
18 Type A bags; 24 Type B bags.
On the graph, the line representing the profit function will be as far as possible from the origin at the point of maximum profit.
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