Answer:
One pair of equivalent expressions is:
x - 3y + 12
12 - 3y - 2x + x + 2x
Second,
x + 3y + 12
3x + 2y - 2x + y + 12
third,
3y + 12
x + 3y + 2x - 3x + 7 + 5
four,
3x + y - 12
4y + 3y + 3x - 6y - 10 - 2
Step-by-step explanation:
In order to match the equivalent expressions we have to put each expression in its simplest form
So,
One pair of equivalent expressions is:
x - 3y + 12
12 - 3y - 2x + x + 2x
Second,
x + 3y + 12
3x + 2y - 2x + y + 12
third,
3y + 12
x + 3y + 2x - 3x + 7 + 5
four,
3x + y - 12
4y + 3y + 3x - 6y - 10 - 2
..
Nanakjanajisnanwj ajnwjwhwbjejs
The concentration of the hydronium ions in the milk is 5.011×10⁻⁴ if the container of orange juice has a pH of 3.3.
<h3>What is pH value?</h3>
The pH of a solution is a measurement of the concentration of hydrogen ions in the solution, as well as its acidity or alkalinity. Normally, the pH scale ranges from 0 to 14.
We have:
A container of orange juice has a pH of 3.3.
The pH value = 3.3
![\rm pH = -log[H_3O^+]](https://tex.z-dn.net/?f=%5Crm%20pH%20%3D%20-log%5BH_3O%5E%2B%5D)
![\rm 3.3 = -log[H_3O^+]](https://tex.z-dn.net/?f=%5Crm%203.3%20%3D%20-log%5BH_3O%5E%2B%5D)
Removing log:
![\rm 10^{-3.3}=[H_3O^+]](https://tex.z-dn.net/?f=%5Crm%2010%5E%7B-3.3%7D%3D%5BH_3O%5E%2B%5D)
![\rm [H_3O^+] = 5.011\times10^{-4}](https://tex.z-dn.net/?f=%5Crm%20%5BH_3O%5E%2B%5D%20%3D%205.011%5Ctimes10%5E%7B-4%7D)
Thus, the concentration of the hydronium ions in the milk is 5.011×10⁻⁴ if the container of orange juice has a pH of 3.3.
Learn more about the pH value here:
brainly.com/question/1503669
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hello
to solve this question, let's try to write out an equation
Answer:
The required expression is y = 1.4 - 0.05x
Step-by-step explanation:
Consider the provided information.
Food mix A contains 2% fat and food mix B contains 7% fat.
Let x kilograms of food A are used, in a 20-kilogram mixture.
Thus, 20 - x kilograms of food B are used, in a 20-kilogram mixture.
Now It is given that A contains 2% fat and food mix B contains 7% fat.
2% and 7% can be written as 0.02 and 0.07 respectively. Let represent the total fat with y.
Thus, the required expression is:
y = 2% (x) + 7% (20 - x)
y = 0.02 (x) + 0.07 (20 - x)
y = 0.02x + 1.4 - 0.07x
y = 1.4 - 0.05x
Hence, the required expression is y = 1.4 - 0.05x
