All categories

3 years ago

2y+3=5x-18. make x the subject

Mathematics

2 answers:

Anestetic [448]3 years ago

5 0

$x = \frac{2y + 21}{5}$

Step-by-step explanation:

1) Add 18 to both sides.

$2y + 3 + 18 = 5x$

2) Simplify 2y + 3 + 18 to 2y + 21.

$2y + 21 = 5x$

3) Divide both sides by 5.

$\frac{2y + 21}{5}$

4) Switch sides.

$x = \frac{2y + 21}{5}$

Hope it helps.

sorry if its wrong.

puteri [66]3 years ago

4 0

Answer:

Step-by-step explanation:

2y+3=5x-18

2y+21 = 5x

x = ⅖y + 21/5

You might be interested in

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

Anna said that the product of 7/8x 1/2=7/2

artcher [175]

Ana is false. The answer is 7/16 because 7*1=7 and 8*2=16

7 0

4 years ago

Read 2 more answers

Kelly simplified this power of a product.

Natalija [7]

Answer:

the answer is D

Step-by-step explanation:

i got it right

5 0

3 years ago

Read 2 more answers

an arc welder provides 250 amps of current when operating with a voltage of 40 volts. what is the power required by this welder

FinnZ [79.3K]

The power(P) of the circuits is the product of the voltage (V) in volts and current(I) in amperes.
P = IV

Substituting the known values to the equation,
P = (250 amps) x (40 volts) = 10,000 Watts

Thus, the answer is 10,000 Watts.

3 0

3 years ago

Read 2 more answers

Drew has 50 red, green, and blue marbles. He has six more red marbles than blue marbles and four fewer green marbles than blue m

Yanka [14]

Drew has 56 Red Marbles, 56 Green Marbles, Drew has about 60 Blue Marbles. First i added 6 to Red since Red Has 6 More Marbles Than Blue, Then i added Subtracted 4 from green, which resulted in 46 Green Marbles. Finally i added 4 and 6 to get 60 Blue Marbles. I am not sure if i am correct, but i gave it a shot! ^-^

4 0

3 years ago

2y+3=5x-18. make x the subject​

2y+3=5x-18. make x the subject