What is the y intercept for y+3= 5(x -3)

P + 17 = 25 2) n − 11 = 8 3) 19 + x = 33 4) x − 1 = 8 5) 15x = 105 6) 8v = 48 7) n + 11

tester [92]

Answer:

3x+4=4

Step-by-step explanation:

3 0

3 years ago

How many is 5 hours in 141.50 hours how many is 5 hours in 141.50 hours

katen-ka-za [31]

141.5 ÷ 5 = 28 with remainder so its just 28

4 0

3 years ago

I NEED HELP ON THIS ASAP PLEASEEEEEEE

olga55 [171]

Answer:

552.6 because 15% × 3684 = 552.6

3684 × 0.15 = 552.6

7 0

3 years ago

Read 2 more answers

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .