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Murljashka [212]
3 years ago
14

What are the first and last deciles of the standard Normal distribution?

Mathematics
1 answer:
aliya0001 [1]3 years ago
5 0

My best Guess is

1.282 for upper . , -1.282 for lower.

Hope this Helps

-Dante

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What is the value of st divided by (6r) if r =5 and t =45
SVEN [57.7K]
Write "st div. by 6r" as

  st
-------
   6r
                                                                                   45s        15s        3s
If r =5 and t = 45, but s is unknown, then we get    --------- = --------- = -------
                                                                                    6(r)        2(5)        2
8 0
3 years ago
Determine 30% of 70.<br><br><br> using double number line
Vadim26 [7]

Answer:

100%     -     70

---------------------

30%      -      x

100x=70*30\\100x=2100\\x=\frac{2100}{100}\\x=21

3 0
3 years ago
Solve the system of equations by substitution.<br> 3/8x + 1/3y = 17/24<br> x + 7y = 8
bixtya [17]
Using the second equation, let’s find x

x + 7y = 8
x = 8 - 7y

Substitute x in the other equation

3/8(8 - 7y) + 1/3y = 17/24
3 - 21/8y + 1/3y = 17/24
-55/24y = -55/24
y = 1

Plug in y in any equation

x + 7(1) = 8
x + 7 = 8
x = 1

x = 1 and y = 1
3 0
3 years ago
The diameter of a circle is 16 kilometers.What is the circle's circumference?​
qaws [65]

The equation to find the circumference of a circle is ...

c = π × d

All we need to do to find circumference is to <em><u>multiply</u></em> the diameter (16km) by pi (π)

c = π × 16

c = 50.27

4 0
3 years ago
Read 2 more answers
A water tank in the shape of an inverted circular cone has a base radius of 3 m and height of 7 m . If water is being pumped int
Wittaler [7]

The water level increases by 0.608 meters per minute when the water is 3.5 m deep

<h3>How to determine the rate?</h3>

The given parameters are:

  • Radius, r = 3
  • Height, h = 7
  • Rate in, V' = 4.3m^3/min

The relationship between the radius and height is:

r/h = 3/7

Make r the subject

r = 3h/7

The volume of a cone is;

V = \frac 13\pi r^2h

This gives

V = \frac 13\pi (\frac{3h}{7})^2h

Expand

V =  \frac{3h^3}{49}\pi

Differentiate

V' = \frac{9h^2}{49}\pi h'

Make h' the subject

h' = \frac{49}{9\pi h^2}V'

When the water level is 3.5.

We have:

h' = \frac{49}{9\pi * 3.5^2}V'

Also, we have:

V' = 4.3

So, the equation becomes

h' = \frac{49}{9\pi * 3.5^2} * 4.3

Evaluate the products

h' = \frac{210.7}{346.36}

Evaluate the quotient

h' = 0.608

Hence, the water level increases by 0.608 meters per minute

Read more about volumes at:

brainly.com/question/10373132

#SPJ1

7 0
2 years ago
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