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Eduardwww [97]
3 years ago
10

Professor Danielle conducts an experiment on chloroplasts by deactivating several enzymes used for light-independent reactions.

All components of light-independent reactions remain present. Would the light-dependent reactions proceed normally? Explain.
PLEASE HELP!!!!
Biology
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

NO.

Explanation:

The process of reaction of CO2 with H20 in the presence of enzyme, chlorophyll and sunlight is called photosynthesis. It has two stages: It is referred to as light dependent stage when it occurs during the day and light independent stage when it occurs at night.

The primary enzyme likely to  be deactivated by the Professor is ribulose bisphosphate  Carboxylate Rubisco. This is the most important enzyme in plants that catalysis the fixation of Co2  with 5C- ribulose bisphosphate  Carboxylase (RuBP) to form3C -Glycerite -3-phospate.(GP).

The GP is reduced by NADP with ATP to form Triose Phosphate (TP). This is the point of glucose production in plants,

The majority of the TP is used for RuBP, hexose phosphates  for starch productions, fatty acid and glycerol for cell membrane.  Amino acids are also produced from TP. This is known s Calvin Cycle.

If the enzyme Rubisco is deactivated, the above process cannot occur, thus the basic macronutrients and enzymes  for the survival of plants for photosynthesis(light dependent stage)  can not occur.

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B. Will using farmland to grow crops for ethanol cause food shortages and increase<br> food prices?
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Explanation:Using the land will take up space where food crops could grow.

7 0
3 years ago
There is a population of alien dogs, species Dogus Cute-ee-us, that live on the planet Woof. Their genomes and biology are amazi
kupik [55]

Answer:

c. 1:4:6:4:1

Explanation:

The term quantitative heritability refers to the transmission of a phenotypic trait in which expression depends on the additive effect of a series of genes.  

Polygenic heritability occurs when a trait results from the interaction of more than one gene. And these genes can also have more than two alleles. The action of many genes and alleles can cause many different combinations that are the reason for genotypic graduation.  

Quantitative traits are those that can be measure, such as longitude, weight, eggs laid per female, among others. In the exposed example, the measurable trait is the dog´s friendliness. These characters do not group individuals by any precise and clear categories. Instead, they group individuals in many different categories that depend on how the genes were intercrossed and distributed during meiosis. The result depends on the magnitude in which each allele contributes to the final phenotype and genotype. When they interact, they create a gradation in phenotypes, according to the level of contribution.  

In the exposed example, each dominant allele contributes with a higher level of friendliness.    

  • aabb → 0 = Unfriendly/Loner (although not aggressive);
  • Aabb, aaBb → 1 = Somewhat friendly/shy;
  • AAbb, AaBb, aaBB → 2 = Friendly;
  • AABb, aABB → 3 = Very friendly;
  • AABB → 4 = Maximally friendly.

Cross: between two dihybrid friendly dogs

Parentals) AaBb    x    AaBb

Gametes) AB, Ab, aB, ab

                AB, Ab, aB, ab

Punnett square)   AB       Ab       aB       ab

                   AB   AABB   AABb  AaBB  AaBb

                    Ab   AABb    AAbb  AaBb  Aabb

                    aB   AaBB    AaBb   aaBB   aaBb

                    ab    AaBb    Aabb   aaBb   aabb

F1) 1/16 AABB ⇒ 4 = Maximally friendly

    4/16 AABb + AaBB ⇒ 3 = Very friendly

    6/16 AAbb + AaBb + aaBB ⇒ 2 = Friendly

    4/16 Aabb + aaBb ⇒ 1 = Somewhat friendly/shy

    1/16 aabb ⇒ 0 = Unfriendly/Loner

The Phenotypic ratio is 1:4:6:4:1

   

6 0
3 years ago
If 35.0 g of CH3OH (MM = 32.0 g/mol) are dissolved in 500.0 mL of solution, what is the concentration of CH3OH in the solution?​
astra-53 [7]

The concentration of CH3OH in the solution is 2.18M

HOW TO CALCULATE MOLARITY:

  • The molarity of a solution can be calculated by dividing the number of moles by its volume as follows:

  • Molarity {M} = no. of moles (mol) ÷ volume (L)

  • According to this question, 35.0 g of CH3OH (MM = 32.0 g/mol) are dissolved in 500.0 mL of solution. The number of moles of methanol is calculated as follows:

no. of moles = 35g ÷ 32g/mol

no. of moles = 1.09mol

  • Molarity = no. of moles ÷ volume

Volume = 500mL = 0.500L

Molarity = 1.09mol ÷ 0.500L

Molarity = 2.18M

Therefore, the concentration of CH3OH in the solution is 2.18M

Learn more at: brainly.com/question/15948514?referrer=searchResults

7 0
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