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babunello [35]
3 years ago
13

Please help it due ASAP I can’t fail pls Bdbdhfhhdudbdmjdvsh please

Mathematics
1 answer:
denis23 [38]3 years ago
5 0
I first found the slope of the line graphed. So i took 2 points and found the slope. They were (2,0) and (0,-3). The slope was 3/2. I then flipped it and added a negative because your looking for the perpendicular line. That was -2/3.

I took the formula y1-y=m(x1-x) and put in -2/3 as m and y1 as 2 and x1 as -1. You plug those into the equation and solve for y.

I got B for the answer

Hope this helps!
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Find C round the answer to the nearest hundredth
Tasya [4]

Answer:

48.85 degrees

Step-by-step explanation:

To find the measure of the angle, use the inverse sine function.

Since Sin C = 55/73, so the inverse sine is sin^{-1} \frac{55}{73}.

Using a calculator, the angle is 48.85 degrees.

3 0
4 years ago
What is the sales tax on a chair with a price tag of $180, if the tax rate is 5.75%?
Anuta_ua [19.1K]

Answer:

$190.35

Step-by-step explanation:

180 ⋅ 0.0575 = 10.35

Add 180 to 10.35

$190.35

(I could be wrong. Sorry if I am)

Hope I helped :)

Please consider Brainliest :)

8 0
3 years ago
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
Find so that the distance between (−2,3) and (,1) is √13
belka [17]

The distance between (-2, 3) and (-5, 1) is √13.

or, the distance between (-2, 3) and (1, 1) is √13.

We know that the length of the line segment connecting any two points represents the distance between them. There is just one line that connects the two points. Therefore, by measuring the length of the line segment that connects the two points, the distance between them can be determined. If (a, b) and (c, d) be two points, then the distance between them is \sqrt[]{(b - a)^{2} +(d- c)^{2} }.

Here, one point is (-2, 3).

Let the other point be (x, 1).

Given that the distance is √13.

Now, \sqrt[]{(x - (-2))^{2} +(1 - 3)^{2} } = \sqrt{13}  

i.e. \sqrt[]{(x + 2)^{2} +( - 2)^{2} } =\sqrt{13}

i.e. \sqrt[]{x^{2}+4x +4 +4 }=\sqrt{13}

i.e. x^{2}+4x +8 =13

i.e. x^{2}+4x + 8- 13=0

i.e.x^{2}+4x -5=0

i.e. x^{2} +5x - x -5=0

i.e. x(x+5)-1(x+5)=0

i.e. (x+5)(x-1)=0

i.e. x=-5,1

So, the point is either (-5, 1) or (1, 1).

Therefore, the required point is either (-5, 1) or (1, 1).

i.e. the distance between (-2, 3) and (-5, 1) is √13.

or, the distance between (-2, 3) and (1, 1) is √13.

Learn more about distance here -

brainly.com/question/431605

#SPJ10

7 0
2 years ago
Solve for x.<br> A)-6<br> B)-9<br> C)-15<br> D)-18
faltersainse [42]
The correct answer is C) -15.

Anyways, I hope you have a wonderful evening :)
8 0
3 years ago
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