Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
You know that the ratio of J&S to F&So is 2:3. You need two numbers that have that same ratio to total 60 players. When you multiply both numbers by 12, you have a ratio of 2:3 but the number of players is 24 to 36. Thus, the total players is 60. When looking at the ratio of Juniors to Seniors, the ratio remains 1:2, but must total 24 players. Dividing the total players by 3, you can find where 1 part of the players equals 2 parts of the others. Keeping that same ratio in mind, you are able to calculate that the ratio of Juniors to Seniors is 8:16 but when reduced, still remains a 1:2 ratio.
See below for solution. Hope this is helpful
Answer:
5.4 > x > 2.8
Step-by-step explanation:
Sum of two sides is always greater than the third side
Case1 :
4.1 + 1.3 > x
5.4 > x
Case2:
4.1 + x > 1.3 or 1.3 + x > 4.1
x > 1.3 - 4.1 or x > 4.1 - 1.3
x > - 2.8 or x > 2.8
Note that it is obvious x is not -ve so neglect -2.8. x > 2.8
Hence,
5.4 > x > 2.8
40
+5
+6
.03
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= 51.03
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