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Tju [1.3M]
3 years ago
15

HELP PLEASE!!!!!!!!!!

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0
6*3= 18
6*3=18
18+18= 36
Answer 36
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Dmitriy789 [7]

Answer:

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Step-by-step explanation:

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3 years ago
Dan bought 8 shirts and 3 pants. Devonte bought 12 shirts and 5 pants. For each person, write a ratio to represent the number of
shutvik [7]

Answer:

Step-by-step explanation:

Dan bought 8 shirts and 3 pants. This means that the ratio representing the number of shirts to the number of pants that Dan bought is 8/3 = 2.67

Devonte bought 12 shirts and 5 pants. This means that the ratio representing the number of shirts to the number of pants that Devonte bought is 12/5 = 2.4

Therefore, they are not equivalent ratios because the relationship is not exactly the same.

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3 years ago
Four brothers work together to mow 3 equal-sized fields. Each brother mows the same amount. How much does each brother mow? Mark
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3 years ago
Read 2 more answers
If 12 cats can catch 6 rats in 2 hours, how many hours would it take 50 cats to catch 75 rats?
sleet_krkn [62]

Answer:

50 cats would take 6 hours to catch 75 rats.

Step-by-step explanation:

After reading the statement we noticed the existence of two relationships:

1) <em>The amount of cats is directly proportional to the quantity of caught rats.</em>

2) <em>The amount of cats is inversely proportional to time taken to catch rats. </em>

That is to say:

n \propto \frac{x}{y}

n = k\cdot \frac{x}{y} (Eq. 1)

Where:

n - Amount of cats, dimensionless.

x - Amount of caught rats, dimensionless.

y - Time, measured in hours.

k - Proportionality ratio, measured in hours.

Then, we obtain the following relationship by eliminating the proportionality ratio in (Eq. 1):

\frac{n_{1}\cdot y_{1}}{x_{1}} = \frac{n_{2}\cdot y_{2}}{x_{2}} (Eq. 2)

Where:

n_{1}, n_{2} - Initial and final amounts of cats, dimensionless.

x_{1}, x_{2} - Initial and final amounts of caught rats, dimensionless.

y_{1}, y_{2} - Initial and final times, measured in hours.

Now we clear final time in (Eq. 2):

y_{2} = y_{1}\cdot \left(\frac{n_{1}}{n_{2}} \right)\cdot \left(\frac{x_{2}}{x_{1}} \right)

By knowing that y_{1} = 2\,h, n_{1} = 12, x_{1} = 6, n_{2} = 50, x_{2} = 75, then we get that time taken by 50 cats to catch 75 rats is:

y_{2} = (2\,h)\cdot \left(\frac{12}{50} \right)\cdot \left(\frac{75}{6}\right)

y_{2} = 6\,h

50 cats would take 6 hours to catch 75 rats.

7 0
4 years ago
The vertex of a parabola is at $(12, -4)$, and its axis of symmetry is vertical. One of the $x$-intercepts is at $(15, 0)$. What
laila [671]

Answer:

9

Step-by-step explanation:

Since the axis of symmetry is vertical and the vertex of the parabola is at (12,-4), the vertical line x=12 is the axis of symmertry. The x-distance between the axis of symmetry and the first x intercept (15,0) is equal to 15-12=3. Hence, this x-intercept is 3 units to the right of the axis, and because it is symmetric, the other x-intercept must be 3 units to the left of the axis, so its x-coordinate must be 12-3=9. Then, the other x-intercept is at the point (9,0)

5 0
4 years ago
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