This is a Pythagorean Theorem problem. 3^2 + 7^2 = 58. C^2 = 58. C = 7.6157 (exact)
There is no exact answer for this. The closest we can get to 58 is 7.6157, which would leave us at 57.9988. So the approximate value is 7.6, but if you need the closest answer, it’s 7.6157.
Area=πr^2
Area=π(16)^2
Area≈804.2477 cm^2
I left the number large enough in case you need to round it off to some other decimal place.
Answer:
Distributive property
Step-by-step explanation:
3(2 − 3x) + 4x = x − 7
Distribute the 3 to each term in the parentheses using the distributive property
6 -9c +4x = x-7
Answer:
13 units
Step-by-step explanation:
(x₁,y₁) = (-5 , 3) & (x₂ , y₂) = (7 ,8)
![= \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\= \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%287-%5B-5%5D%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B%287%2B5%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%20%5Csqrt%7B%2812%29%5E%7B2%7D%2B%285%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B144%2B25%7D%5C%5C%5C%5C%3D%5Csqrt%7B169%7D%5C%5C%5C%5C%3D%2013)
Answer:
Since the square root of 25 = 5 and the square root of 36 is 6 it is known that the square root of 33 is between 5 and 6.
Step-by-step explanation:
The key to this is to think about perfect squares, specifically the ones closest to 33. These are 25 and 36, which have square roots of 5 and 6 respectively. Because 33 is between these numbers, you know for certain that its square root is between <em>their</em> square roots too.
Let me know if you need a more in-depth explanation!
