The x - coordinate of the solution is 
Explanation:
The two equations are
and 
Let us determine the value of the x - coordinate using the substitution method.
Let us substitute
in the equation
, we get,

Multiplying the term 3 within the bracket, we get,

Subtracting both sides of the equation by 6, we get,

Taking LCM on the LHS of the equation, we get,

Subtracting the numerator, we have,

Multiplying both sides of the equation by 2, we have,

Dividing both sides of the equation by 3, we get,

Thus, the x - coordinate of the solution is 