They both have to be above the x axis, which makes B incorrect. B will be below the x axis. If you have a graphing calculator or know where there is one of the net, you can try it.
A and D are both wrong. The 1/2 does not become 2. What will happen is that 2 will make the graph wider.
There's only 1 answer left and that is
C <<<<<===== answer.
C reflects right across the y axis.
Answer:
(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0
(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0
Step-by-step explanation:
(a) when i = 2, the expected number of played games will be:
E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] = 4p²-4p+2-6p²+6p = -2p²+2p+2.
If p = 1/2, then:
d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.
(b) when i = 3;
E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]
Simplification and rearrangement lead to:
E(X) = 6p⁴-12p³+3p²+3p+3
if p = 1/2, then:
d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10
Therefore, E(X) is maximized.
Answer:
The other rational number is 
.
Step-by-step explanation:
First rational number is 
Let other rational number is 
The product of two rational numbers is 
According to question,
Multiplying both sides by (-3/2) such that,
So, the other rational number is .
Answer:
30%
Step-by-step explanation:
Find the total number of candies in the jar.
8 + 5 + 1 + 6 = 20
The probability of choosing a green candy is 6/20 = 3/10 = .3 = 30%
Given equation of hyperbola is
Given hyperbola is the horizontal hyperbola
The standard form of the horizontal hyperbola is
When we compare these two equations, we get
h = 1, a = 5 , k = -3 and b = 3
Length of the transverse axis = 2a
Plug in the value of 'a' as 5
So,Length of the transverse axis = 2(5) = 10
