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earnstyle [38]
3 years ago
6

Please help geometry !

Mathematics
1 answer:
malfutka [58]3 years ago
8 0
Point E and point D, (brainliest answer please)
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in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok
grandymaker [24]

Answer:

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

\hat p=0.849 estimated proportion of adults were no longer smoking after one month

p_o=0.80 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:  

Null hypothesis:p=0.8  

Alternative hypothesis:p \neq 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

6 0
3 years ago
Which shows the image of quadrilateral ABCD after the transformation R0, 90°?
avanturin [10]

Answer:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

Step-by-step explanation:

The coordinates of rectangle ABCD are A(-1,0), B(0,-1), C(-2,-3), (-3,-2).

The mapping for a rotation through 90° clockwise about the origin is

(x,y)\to ( - y,x)

Therefore:

A(-1,0)\to A'(0,-1)

B(0,-1)\to B'(1,0)

C(-2,-3)\to C'(3,-2)

D(-3,-2)\to D'(2,-3)

Therefore the image rectangle has coordinates:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

The first choice is correct.

4 0
3 years ago
Read 2 more answers
Two lines intersect. Find the values of b and c.
Mandarinka [93]

Step-by-step explanation:

I think b is 42 as well cause there are vertically opposite

ummm ....and c is (180- 42 because they are adjacent angles)

therefore b=42

c= 138

that is what I yhink sorry if it ain't the right answer

3 0
3 years ago
Read 2 more answers
Please help! 90 x 120 = ? divided by 2
Anna007 [38]

90 x 120 = 10800

10800/2 = 5400

6 0
2 years ago
Read 2 more answers
Why might a person need an emergency fund?
neonofarm [45]
Why An Emergency Fund<span> Is Important. People who've had large and unforeseen expenses arise can probably either tell you how happy they were that they had</span>emergency fund<span>s, or how difficult it was to find the money to cover expenses.</span>
4 0
3 years ago
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