MN is the mid-line of a trapezoid HJLK.<span>
The length of the mid-line of a trapezoid is half of the sum of the lengths of its bases </span>⇒
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(KL + HJ)/2 = MN
(KL + 45)/2 = 28
KL + 45 = 28 * 2
KL + 45 = 56
KL = 56 - 45
KL = 11
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Just add Vickie and Hannah's scores together. Simple addition problem. You end up with 3056+1686=4742.Final answer is 4742 points.
Answer:
The model is shown in the attached picture. The solution is 10.
Step-by-step explanation:
There are two way of showing a model for 2×5
- The tape diagram has 2 equal-sized parts of 5
- The tape diagram has 5 equal-sized parts of 2
Both models give the same solution:
- 5+5=10
- 2+2+2+2+2=10
In the attached picture we can show two types of diagram.
X= 130°
Step-by-step explanation:
From E, draw EF || AB || CD.
Now, EF || CD and CE is the transversal.
So; <DCE + <CEF = 180° [co. int. <s]
x° + <CEF = 180°
<CEF = (180° – x°).
Again, EF || AB and AE is the transversal.
So; <BAE + <AEF = 180° 01 [co. int. <s ]
105° + <AEC+ <CEF = 180°
105° +25° + (180° – x°) = 180°
x° = 130°
I hope I helped you^_^
