All categories

3 years ago

PLEASE HURRY!! The graph shows the distance traveled by two cars over several minutes.

Mathematics

2 answers:

tamaranim1 [39]3 years ago

6 0

Im late but i had this test its car A < rate of car B hope it helps

Genrish500 [490]3 years ago

4 0

Answer:

Rate of Car A < Rate of Car B

Step-by-step explanation:

The given graph shows the distance traveled by two cars over several minutes.

Two lines, labeled Car A and Car B, exit the origin to show that distance increases as time increases.

We know that steeper line has greater rate of change.

From the given graph it is clear that the line of Car B is steeper than the line of car A. It means the rate of car B is greater than rate of car A.

Rate of Car A < Rate of Car B

Or it can be written as

Rate of Car B > Rate of Car A

You might be interested in

An on-demand movie company charges $2.95 per movie plus a monthly fee of $39.95. Which expression represents the yearly cost for

natulia [17]

Answer:

y=$2.95x+$479.4

Step-by-step explanation:

Let

x----> the number of movie rentals

y ----> the cost for movie rentals

we know that

The expression that represent the monthly cost is equal to

y=$2.95x+$39.95

1 year has 12 months

The expression that represent the yearly cost is equal to

y=$2.95x+$39.95*(12)

y=$2.95x+$479.4

8 0

3 years ago

In circle O, which segment is a diameter? a) RC b) SD c) CO d) OH

kupik [55]

RC is the diameter. As you can see, it runs across the circle.

I hope this helped you.

Brainliest answer is always appreciated.

5 0

4 years ago

Read 2 more answers

The amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and standard deviation 13 mL. Supp

andreyandreev [35.5K]

Answer:

(a) X ~ N( $\mu=63, \sigma^{2} = 13^{2}$ ).

$\bar X$ ~ N( $\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}$ ).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

Step-by-step explanation:

We are given that the amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and a standard deviation of 13 mL.

Suppose that 43 randomly selected people are observed pouring syrup on their pancakes.

(a) Let X = amount of syrup that people put on their pancakes

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean amount of syrup = 63 mL

$\sigma$ = standard deviation = 13 mL

So, the distribution of X ~ N( $\mu=63, \sigma^{2} = 13^{2}$ ).

Let $\bar X$ = sample mean amount of syrup that people put on their pancakes

The z-score probability distribution for the sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean amount of syrup = 63 mL

$\sigma$ = standard deviation = 13 mL

n = sample of people = 43

So, the distribution of $\bar X$ ~ N( $\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}$ ).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < X < 62.8 mL)

P(61.4 mL < X < 62.8 mL) = P(X < 62.8 mL) - P(X $\leq$ 61.4 mL)

P(X < 62.8 mL) = P( $\frac{X-\mu}{\sigma}$ < $\frac{62.8-63}{13}$ ) = P(Z < -0.02) = 1 - P(Z $\leq$ 0.02)

= 1 - 0.50798 = 0.49202

P(X $\leq$ 61.4 mL) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{61.4-63}{13}$ ) = P(Z $\leq$ -0.12) = 1 - P(Z < 0.12)

= 1 - 0.54776 = 0.45224

Therefore, P(61.4 mL < X < 62.8 mL) = 0.49202 - 0.45224 = 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < $\bar X$ < 62.8 mL)

P(61.4 mL < $\bar X$ < 62.8 mL) = P( $\bar X$ < 62.8 mL) - P( $\bar X$ $\leq$ 61.4 mL)

P( $\bar X$ < 62.8 mL) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{62.8-63}{\frac{13}{\sqrt{43} } }$ ) = P(Z < -0.10) = 1 - P(Z $\leq$ 0.10)

= 1 - 0.53983 = 0.46017

P( $\bar X$ $\leq$ 61.4 mL) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{61.4-63}{\frac{13}{\sqrt{43} } }$ ) = P(Z $\leq$ -0.81) = 1 - P(Z < 0.81)

= 1 - 0.79103 = 0.20897

Therefore, P(61.4 mL < X < 62.8 mL) = 0.46017 - 0.20897 = 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

4 0

3 years ago

Which of these systems of equations shows the solution for the graph?

I am Lyosha [343]

Answer:

Step-by-step explanation:

Note that one of the lines is simply y=-1 for any x, so we can dismiss the only answer without y=-1. That rejected answer is A)

Now let's notice, that the other line is decreasing y when increasing x. That tells us that in the equation y = ax + b, a has to be negative. This brings us to reject option D).

What is the y of that line for x = 0? Because y = ax + b, for x = 0 we will get the value of b. This is called the intercept. The line is at y=4 for x=0, so we know that the b in the equation must be positive 4. This fits answer C, but rejects answer B). And so, we have found that C) is the only possible answer.

4 0

3 years ago

What measurement is equelvent to 3 meters

Lelu [443]

Answer:

The Chi and Zhang were units of length equivalent to approximately 25 centimeters (9.8 inches) and 3 meters (9.8 feet) respectively.

Step-by-step explanation: 300 centimeters if you need metric measurements.

4 0

3 years ago