10×5+4 2 +(5+30÷10) Order Of Operations

Mathematics

1 answer:

Oxana [17]3 years ago

8 0

Answer:

100.

Step-by-step explanation:

When an equation like this shows ip, the best way to solve it is by using B(brackets) I(indices*such as minus numbers) D(divide) M(multiply) A(add) S(subtract)

So we would do, (5+30÷10) first, because B(brackets is first). Divide comes before add, so we do 30÷10 first which is, 3. Then we do 5+3, which is 8. Now we would do the other section, 10x5+42. We do 10x5 first (becuase multiply is before add) which is, 50. Then we do, 50+42 which is, 92. Now with both our final answers we add them together, 92+8=100.

Hope this helped in some way (p.s this is how I do it in my school)

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A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are

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Area(A)=Area(C)= $9 in^{2}$

Area(B)= $13.2 in^{2}$

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

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a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)= $\frac{b*h}{2}$ = $\frac{6*3}{2}$ = $9 in^{2}$

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

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