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ki77a [65]
2 years ago
7

Helen told her mom she got 85% on a recent math test. She remembered the test was out of 60. What was her actual mark? *

Mathematics
1 answer:
barxatty [35]2 years ago
8 0

Answer: 85% out of how many questions.

Step-by-step explanation:

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Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$
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\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy
\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy
\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}
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4 0
3 years ago
Help please! Need help solving
NISA [10]
For the perimeter you have to consider the EXTERNAL SHAPE ONLY:

a) the perimeter of half a circle WITHOUT ITS DIAMETER  is:
π.R - 2R → 3.14x1.5 - 2x1.5 → 1.71 cm

b) the perimeter of the rectangle WITHOUT THE UPPER SIDE is:
2.5+3+2.5 = 8 cm

Hence the perimeter of the figure is 1.71 + 8 = 9.71 cm

2) Area of the figure:
Area of half circle is π.R²/2 →3.14 x (1.5)²/2 → Area half circle = 3.5325 cm²
Area of rectangle = 2.5 x 3 = 7.5 cm²
Total area = 3.5325 + 7.5 = 11.0325 ≈ 11 cm²


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3 years ago
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domain x   [0,4]     range y  [0,64]

Step-by-step explanation:

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A gymnastics coach records the scores of a gymnast and develops the probability distribution below. What is the
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Step-by-step explanation: took the review and got it right

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Step-by-step explanation:

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