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Sladkaya [172]
2 years ago
15

Given the measures a = 10, b = 40, and A = 30°, how many triangles can possibly be formed?

Mathematics
1 answer:
arlik [135]2 years ago
8 0

Answer:

no triangle can be formed with the given values (i.e 0 triangle).

Step-by-step explanation:

Given;

length of side a, = 10

length of side b, = 40

angle A, = 30°

Apply sine rule to determine the angle of the second side (B);

\frac{sin \ A}{a} = \frac{sin \ B}{b} \\\\\frac{sin \ 30^0}{10} = \frac{sin \ B}{40}\\\\sin \ B = 40(\frac{0.5}{10} )\\\\sin \ B = 2

The maximum sine function is 1, there is no sine function that will be equal to 2, so there is no triangle that can be formed with the given values.

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