What is the mode of the following set of data? 34, 23, 12, 11, 11, 25, 25, 26, 25, 27, 30
Olin [163]
1 - B
Mode - The mode the number that appears most often in a data set. In this question, 25 was repeated 3 times and no other ones where repeated 3 times. Thats why 25 is the mode.
2 - D
Median - The middle number of a data set that is arranged from least to greatest.
3 - True
There is no mode because all of the numbers only appear once.
4 - A
5 - C
Answer:
sorry where is figure.
Step-by-step explanation:
area of triangle ABE=area of triangle BE3
No, the answer is 24th.
The LCM of 3 and 4 is 12.
(3,6,9,12)(4,8,12)
12th April +12=24th April
Answer:
5091 Km/hr and 505 km/hr
Step-by-step explanation:
Speed = Distance / Time
Let the speed of first automobile be 'x' and that of the second be 'y'
Since speed of one is 10 times greater than the other. therefore;
⇒ x = 10 y
also let time for faster automobile be 'T' and time for slower auto mobile be 't'
Since first arrive one hour earlier than second, therefore;
⇒ t = T + 1
⇒ For first automobile;
; substituting for 'x' and 'T'. Therefore;
⇒ 
⇒ For Second automobile;
⇒ 
⇒ 
⇒ 5600 +
= 560
⇒ 5600 - 560 = - 
⇒ t = 1.11 hr
also ; T = 1.11 - 1 = 0.11 hr
Speed of 1st auto = 560/0.11 = 5091 km /hr
Speed of 2nd auto = 560/1.11 = 505 km/hr
The horizontal distance from the helicopter to the landing pad is 1658.81 feet
<em><u>Solution:</u></em>
The figure is attached below
Triangle ABC is a rightangled triangle
A helicopter is flying at point A and landing pad is at point c
Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees
The helicopter is 1250 feet from the ground
Therefore, AB = 1250 feet
To find: horizontal distance from the helicopter to the landing pad
BC is the horizontal distance from the helicopter to the landing pad
BC = ?
By the definition of tan,


Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet