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horrorfan [7]
3 years ago
7

Hey can some some please help me !!!!!

Mathematics
2 answers:
irga5000 [103]3 years ago
5 0

Answer:

y = x+2

Step-by-step explanation:

proportional relationships are of the form

y = kx where k is a constant

y = x is proportional with k=1

y = 2x is proportional with k =2

y = x+2 is linear

Alona [7]3 years ago
3 0

Answer:

y = x+2

Step-by-step explanation:

proportional relationships are of the form

y = kx where k is a constant

y = x is proportional with k=1

y = 2x is proportional with k =2

y = x+2 is linear

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Phoenix [80]

Answer:

2,309.2

This could be wrong but I'm pretty sure it's right

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2 years ago
What is cos 30º?<br> O A. 13<br> B. 1<br> Oc.<br> O D.<br> 3<br> 2<br> E.<br> O F. 1 /
babunello [35]

Answer: I do not understand the options you gave but but cos30º is equal to \sqrt{3}/2 which is 0.86602540378.

7 0
3 years ago
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svp [43]

Answer:

920

Hope that this helps!

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3 years ago
Solve the following system of equations. Write each of your answers as a fraction reduced to lowest terms. In other words, write
morpeh [17]

Answer:

x = 57/28

y = -95/84

z = 97/168

Step-by-step explanation:

Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html

Start with the expanded array:

\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]

then using the tool provided, make row operations until you find the solution:

r2 = r2-3r1

\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]

r3 = r3+2r1

\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]

r2 = r2*(-1/13)

\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]

r1 = r1- r2*5

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]

r3 = r3+ r2*-3

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]

r3 = r3*13/168

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]

r2 = r2- r3*22/13

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]

r2 = r2+ r3*6/13

\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]

Here you have a reduced array an therefore the answers to each variable are on each row:

\left[\begin{array}{c}x\\y\\z\end{array}\right]

8 0
3 years ago
Square root(50x^2y^3)
leonid [27]
If you are asking to simplify, this is what I got. Hope I was able to help

3 0
3 years ago
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