How is my graphs line be for this question?

What is the solution for x in the equation

devlian [24]

Answer:

C. x=5/2

Step-by-step explanation:

-2x+10x=34-14

(8x=20 ) /:8

x=5/2

3 0

3 years ago

Annie needs $30 to buy a coat. She has saved $12 and plans to work as a babysitter to earn $6 per hour. Which inequality shows t

algol [13]

Annie's total earnings from her initial savings, $12, and from babysitting should be equal or more than 30. Annie's total earnings from babysitting may be expressed as $6n. The inequality should be,

12 + 6n ≥ 30

Solving for x,
6n ≥ 30 - 12

6n ≥ 18 ; n ≥ 3

Thus, the answer is the second among the choices.

6 0

3 years ago

Read 2 more answers

Question 1

Black_prince [1.1K]

C:x, in the bottom equation

4 0

2 years ago

Question 13 pls. Brainliest for the first answer

tankabanditka [31]

Answer: a child ticket costs $14.50

Step-by-step explanation:

x=children ticket

x+4.50=adult ticket

3 children and 2 adult

3x+2(x+4.50)=81.50

3x+2x+9.00=81.50

5x+9.00=81.50

5x+9.00-9.00=81.50-9.00

5x=72.50

5x/5=72.50/5

x=14.50

7 0

3 years ago

Five hundred eleven (511) homes in a certain southern California community are randomly surveyed to determine if they meet minim

allsm [11]

Answer:

The confidence interval at the 90% confidence level for the true population proportion of southern California community homes meeting at least the minimum recommendations for earthquake preparedness is (0.3136, 0.3830).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

511 homes were surveyed, of which 178 met the minimum recommendations for earthquake preparedness. This means that $n = 511$ and $p = \frac{178}{511} = 0.3483$ .

Find the confidence interval at the 90% confidence level for the true population proportion of southern California community homes meeting at least the minimum recommendations for earthquake preparedness.

So $\alpha = 0.10$ , z is the value of Z that has a pvalue of $1 - \frac{0.10}{2} = 0.95$ , so $z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3483 - 1.645\sqrt{\frac{0.3483*0.6517}{511}} = 0.3136$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3483 + 1.645\sqrt{\frac{0.3483*0.6517}{511}} = 0.3830$

The confidence interval at the 90% confidence level for the true population proportion of southern California community homes meeting at least the minimum recommendations for earthquake preparedness is (0.3136, 0.3830).

6 0

2 years ago