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labwork [276]
3 years ago
10

The 10,000-meter long-distance running event in the summer Olympics is approximately 6.2 miles. Which equation could be used to

determine the time, t, it takes to run 10,000 meters as a function of the average speed, s, of the runner where t is in minutes and s in miles per minute?
Mathematics
1 answer:
melomori [17]3 years ago
7 0

Answer:

\bold{t = f(s) = \dfrac{6.2}{s}}

Step-by-step explanation:

Given that distance is 10,000 meter or 6.2 miles.

Time taken is t minutes.

Average speed is s miles/minutes

To find:

Equation to determine time 't' as a function of average speed 's' = ?

t is in minutes and

s is in miles/minute

Solution:

First of all, let us have a look at the formula for Average Speed:

\text{Average Speed} = \dfrac{\text{Total Distance Traveled}}{\text{Total Time Taken}}\\\Rightarrow \text{Total Time Taken} = \dfrac{\text{Total Distance Traveled}}{\text{Average Speed}}\\

Now, we are given that Time, t should be in minutes and

Average speed, s must be in miles per minute

That means, we must have distance in miles.

Putting all the values in above formula.

So, the formula or equation becomes:

t = \dfrac{6.2}{s}

Therefore the equation to find time, t in minutes as a function of Average Speed, s is given as:

\bold{t = f(s) = \dfrac{6.2}{s}}

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Answer:

The measure of the angle JKG is:

m∠JKG = 56°

Step-by-step explanation:

<u>Given</u>

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J is a midpoint of the segment FG and K is a midpoint of the segment GH.

<u>To determine</u>

m∠JKG = ?

Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH

We know that two triangles are similar if the only difference is size. So, the angles remain the same.

so m∠JKG and m∠FHK are equal.

i.e.

m∠JKG = m∠FHK

substitute m∠JKG = 76-2x and m∠FHK = 6x-4

76-2x = 6x-4

6x+2x = 76 + 4

8x = 80

divide both sides by 8

8x/8 = 80/8

x = 10

Therefore, the value of x = 10

As

m∠JKG = 76-2x

substitute x = 10

m∠JKG = 76 - 2(10)

             = 76 - 20

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Therefore, measure of the angle JKG is:

m∠JKG = 56°

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