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Maksim231197 [3]
3 years ago
15

A research group is comparing the learning outcomes of students who are taught a lesson using four different teaching techniques

. There are 75 students in the school who can participate in the experiment. Using a table of random digits, the researchers will randomly place the students into five equally sized treatment groups suitable for comparison, four of which will receive a different teaching technique and one of which will remain a control group.
Which design is the most appropriate for this experiment?

A Randomly number each person with 1, 2, 3, 4, or 5. Assign the students to the treatment groups based on their label.
B Select a student, and identify the first digit reading from left to right on a random number table. If the first digit is 1 or 2, assign that student to the technique 1 group. Similarly, digits 3 or 4, 5 or 6, 7or 8, and 9 or 0 go with the technique 2, technique 3, technique 4, and control groups, respectively. Repeat this process for each student.
C Number each student from 1 to 75. Reading the numbers from left to right on a random number table, identify 60 unique numbers from 1 to 75. Assign the students whose labels are the first 15 numbers to the technique 1 group. Assign the students whose labels are the second 15 numbers to the technique 2 group. Repeat this process two more times to assign the technique 3 and technique 4 groups. Finally, assign the remaining students to the control group.
D Number each student from 00 to 74. Reading the numbers from left to right on a table of random numbers and looking at two digits at a time, identify 60 unique two-digit numbers from 00 to 74. Assign the students whose labels are the first 15 numbers to the technique 1 group. Assign the students whose labels are the second 15 numbers to the technique 2 group. Repeat this process two more times to assign the technique 3 and technique 4 groups. Finally, assign the remaining students to the control group.
Mathematics
2 answers:
Kisachek [45]3 years ago
8 0

Answer:

D

Step-by-step explanation:

edge 2021

Triss [41]3 years ago
6 0

Answer:

what is this

Step-by-step explanation:

is this a paragraph

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Step by step show my work to 1650 divided by 55
EleoNora [17]

     ----------<span>55 | 165<span>0
 

</span></span>        <span>30
</span>      ---------<span><span>55 | 1650
</span><span>        165
        --------
           00


</span></span><span> 1650 ÷ 55 = 30..
</span>
Hope it helps !!!!
3 0
3 years ago
Ali deposits her $412.60 paycheck and
wel

Answer:

$617.45

Step-by-step explanation:

315.85+412.60-3×40

= 315.85+412.60-120

=617.45

4 0
3 years ago
Help help help help please!!!!
Ilya [14]

Answer:

74 feet

Step-by-step explanation:

24^2 + 70^2 = 74^2

Pythagorean Theorem

5 0
3 years ago
Simplify. Write in scientific notation. 0.5(8 * 10^5). A. 8*5^5. B. 4*5^5. C. 8*10^5. D. 4^10^5
Alika [10]

it would be 4×10^{5}

8 0
3 years ago
In evaluating a double integral over a region D, a sum of iterated integrals was obtained as follows:
BabaBlast [244]

Answer

a=0, b=2

g_1(x)=\frac{5x}{2},  g_2(x)=7-x

Step-by-step explanation:

Given that

\int \int   Df(x,y)dA=\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy+\int_5^7\int_0^{7-y} f(x,y)dxdy\; \cdots (i)

For the term  \int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy.

Limits for x is from x=0 to x=\frac {2y}{5} and for y is from y=0 to y=5  and the region D, for this double integration is the shaded region as shown in graph 1.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=\frac{5x}{2} to y=5 and limits of x become from x=0 to x=2 as shown in graph 2.

So, on reversing the order of integration, this double integration can be written as

\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx\; \cdots (ii)

Similarly, for the other term  \int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy.

Limits for x is from x=0 to x=7-y and limits for y is from y=5 to y=7  and the region D, for this double integration is the shaded region as shown in graph 3.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=5 to y=7-x and limits of x become from x=0 to x=2 as shown in graph 4.

So, on reversing the order of integration, this double integration can be written as

\int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy=\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx\;\cdots (iii)

Hence, from equations (i), (ii) and (iii) , on reversing the order of integration, the required expression is

\int \int   Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx+\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx

\Rightarrow \int \int   Df(x,y)dA=\int_0 ^2\left(\int _ {\frac {5x}{2}}^5 f(x,y)+\int _5 ^ {7-x} f(x,y)\right)dydx

\Rightarrow \int \int   Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^{7-x} f(x,y)dydx\; \cdots (iv)

Now, compare the RHS of the equation (iv) with

\int_a^b\int_{g_1(x)}^{g_2(x)} f(x,y)dydx

We have,

a=0, b=2, g_1(x)=\frac{5x}{2} and g_2(x)=7-x.

3 0
3 years ago
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