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Pachacha [2.7K]
2 years ago
13

Cellus The figure below is a rhombus. 630 x y = Enter

Mathematics
1 answer:
sleet_krkn [62]2 years ago
6 0

Answer:

y=27

Step-by-step explanation:

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144 is the answer


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Find the product of<br> (x2 + 3x + 1)(x2 + x + 2)
Bogdan [553]

Answer: x^4+4x^3+6x^2+7x+2

Step-by-step explanation:

To solve the exercise you must apply the following proccedure:

- Apply the distributive property.

- Keep on mind that when you multiply two powers with equal base, you must add the exponents.

- Add like terms.

Therefore, you obtain the following product:

=x^{(2+2)}+x^{(2+1)}+2x^2+3x^{(1+2)}+3x^{(1+1)}}+6x+x^{2}+x+2\\=x^4+x^3+2x^2+3x^3+3x^2+6x+x^2+x+2\\=x^4+4x^3+6x^2+7x+2

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Carter digs a hole at a rate of 3/4 feet every 10 minutes. After digging for 30 minutes, Carter places a bush in the hole that f
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the calibration of the system

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6 0
2 years ago
I need help, please. PLEASE, I NEED IT FAST.
Amiraneli [1.4K]

Answer:

Hint: x is a negative number.

Step-by-step explanation:

The equation is x + 12 = -6 and you are trying to find x. The easiest way to solve this equation is by first subtracting 12 from both sides. It would look like x + 12 - 12 = -6 - 12. Since positive 12 and negative 12 are opposite and equal, they cancel each other out. This can be drawn as well into circles and crossed out for every positive circle with a negative circle. As for -6 and -12, you can use the same method of drawing circles, (trust me they can be very helpful, especially for people like me who need to see it visually before getting a hang of it). Since both are negatives, you would have to add them together and that would give you x.

(Please reply if you still have questions. :) Have a wonderful day)

8 0
3 years ago
Explain how you can tell , without computing, whether the quotient 1/2 divided 6 is greater than 1 or less than
nydimaria [60]

Well without even doing it you can tell its less than one here are some reasons why,

  1. The number we are dividing is already less than 1
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  3. It just is.
4 0
2 years ago
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