(2-7m^6)^2
rearrange terms:
(2-7m^6)^2
(-7m^6 + 2)^2
expand the squares:
(-7m^6 + 2)^2
(-7m^6 + 2)(-7m^6 + 2)
distribute:
(-7m^6 + 2)(-7m^6 + 2)
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
distribute:
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
49m^12 - 14m^6 + 2(-7^6 +2)
distribute:
49m^12 - 14m^6 + 2(-7^6 +2)
49m^12 - 14m^6 - 14m^6 + 4
combine like terms:
49m^12 - 14m^6 - 14m^6 + 4
49m^12 - 28m^6 + 4
solution:
49m^12 - 28m^6 + 4
please mark brainliest and hope it helps
Answer:
5391.76
Step-by-step explanation:
We have a rectangle and 2 semicircles
First find the area of the rectangle
A = l*w
A = 44*88= 3872
Then we know that 2 semicircles = 1 circle
The area of a circle is
A = pi r^2
The diameter is 44 so the radius is 22
A = pi * 22^2
A = pi484
A =1519.76
Add the areas together
1519.76+3872
5391.76
Use the formula slope= y-y/x-x
-10-r/-2-8= 1/10
-10-r/-10= 1/10
Multiply the denominator (-10) on both sides
-10-r= -1
Add -10 to both sides
-r= 9
r= -9
Hope this helps!
The value of x is 34.64 feet
<h3>Right-angled triangle</h3>
Find the diagram attached
- The height of the tent = 40 ft
- length of the rope = x
Get the value of x using the SOH CAH TOA identity
Hence the value of x is 34.64 feet
Learn more on SOH CAH TOA here: brainly.com/question/20734777
