Answer: 1460.06
Explanation: google
Answer:
The 90% confidence interval for population mean length of eastern rods is (23.73, 24.07).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean when the population standard deviation is not known is:
![CI=\bar x\pm t_{\alpha/2, (n-1)}\ \frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x%5Cpm%20t_%7B%5Calpha%2F2%2C%20%28n-1%29%7D%5C%20%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
The information provided is:
![n=25\\\bar x=23.9\ \text{feet}\\s=0.50\ \text{feet}\\t_{\alpha/2, (n-1)}=t_{0.05, 24}=1.71\\](https://tex.z-dn.net/?f=n%3D25%5C%5C%5Cbar%20x%3D23.9%5C%20%5Ctext%7Bfeet%7D%5C%5Cs%3D0.50%5C%20%5Ctext%7Bfeet%7D%5C%5Ct_%7B%5Calpha%2F2%2C%20%28n-1%29%7D%3Dt_%7B0.05%2C%2024%7D%3D1.71%5C%5C)
Compute the 90% confidence interval for population mean length of eastern rods as follows:
![CI=\bar x\pm t_{\alpha/2, (n-1)}\ \frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x%5Cpm%20t_%7B%5Calpha%2F2%2C%20%28n-1%29%7D%5C%20%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
![=23.9\pm 1.71\times\frac{0.50}{\sqrt{25}}\\\\=23.9\pm 0.171\\\\=(23.729, 24.071)\\\\\approx (23.73, 24.07)](https://tex.z-dn.net/?f=%3D23.9%5Cpm%201.71%5Ctimes%5Cfrac%7B0.50%7D%7B%5Csqrt%7B25%7D%7D%5C%5C%5C%5C%3D23.9%5Cpm%200.171%5C%5C%5C%5C%3D%2823.729%2C%2024.071%29%5C%5C%5C%5C%5Capprox%20%2823.73%2C%2024.07%29)
Thus, the 90% confidence interval for population mean length of eastern rods is (23.73, 24.07).
I'm fairly sure that the answer is an ecosystom.
For this we can do 5.2 cents times 1.5 to determine how much zippy is costing the company per box extra so .052 x 1.5 is roughly 7.8 cents per box. So now 7.8 cents Times 484, .078 x 484 is roughly $37.752 cents or $37.75