WANR: 22%
WWCN: 41%
WCLM: 24%
WKOD: 13%
However is B. WWCN.
2 because you make them with the same denominators that both go into each other EX: 8x9=72 7/8 now equals 63/72 and 4/9 now equals 28/72 now add them together 63/72 + 28/72= 91/72= 1 19/72
6x+3y=15
6*2+3y=15
12+3y=15
3y=3
y=1
6x+3y=15
6*5+3y=15
30+3y=15
3y=-15
y=-5
The answers is y=1 & -5
Answer:
>.
Step-by-step explanation:
93/100 = 0.93
2/5 = 0.4, so:
93/100 > 2/5.
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
