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aleksandr82 [10.1K]
2 years ago
11

If the parent function is fx) = x^3 which transformed function is shown in the graph?

Mathematics
1 answer:
34kurt2 years ago
6 0

Answer:

g(x) = (x-3)³ is the transformed function.

Step-by-step explanation:

Horizontal shift:

If f(x) is the parent function.

Then horizontal shift can be expressed as:

, will shift left   units.

y = f(x - c), will shift f(x) right c units.

Given the parent function

f(x) = x³

From the graph, it is clear that the transformed function is indicating that the parent function has been horizontally shifted right 3 units.

Therefore, according to the rule, y = f(x - c):

g(x) = (x-3)³ is the transformed function.

From the graph,

  • The Red graph indicates the parent function i.e. f(x) = x³
  • The Blue graph indicates the transformed function i.e. g(x) = (x-3)³

It is clear that the blue graph is obtained when the parent function has been horizontally shifted right 3 units.  

Therefore, g(x) = (x-3)³ is the transformed function.

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Answer: ? Maybe 3???

Step-by-step explanation:

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a stack of cards is placed next to a ruler, and the height of stack measured to be 3/4inches. how thick is one card
4vir4ik [10]

Total thickness of the stack of cards = 3/4 inch or 0.75 inch

In a full stack of cards, there are 52 cards.

Hence, the thickness of 52 cards = 0.75 inch.

To find the thickness of one card, we divide the total thickness with the total number of cards.

Thickness of one card = \frac{0.75}{52} = 0.014423 inch

1 inch = 2.54 cm

0.014423 inch is approximately equal to 0.34 cm.

Answer = 0.34 cm

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3 years ago
11. Circle the name of the student who correctly wrote the equation modeled below. Then, find the
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Answer:

the student that is correct is Gene and the solution is x=10

3 0
2 years ago
7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many
BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>
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