Question

A bag contains 3 red, 4 blue, and 6 yellow marbles. One marble is selected at a time, and once a marble is selected, it is not replaced. Find the probability of choosing two yellow marbles. P(yellow, yellow)

Answer 1

The probability of choosing two yellow marbles = 5/26

Step-by-step explanation:

Step 1 :

Given

Total number of marbles in the bag = 13 marbles

Number of yellow marbles = 6.

We choose 2 marbles from the bag without replacing and need to determine the probability that both are yellow.

Step 2 :

Probability of finding yellow marble in the first try = Number of yellow marbles / Total number of marbles = $\frac{6}{13}$

Once the yellow marble is selected we have 5 yellow marbles among 12 remaining marbles in the bag.

Probability of finding yellow marble in the second try = Number of yellow marbles / Total number of marbles = $\frac{5}{12}$

Step 3:

P(yellow in first 2 tries) = P(yellow in first try) * P(yellow in second try)

P(yellow in first 2 tries) = $\frac{6}{13} * \frac{5}{12}$ = $\frac{5}{26}$

Step 4:

Answer:

The probability of choosing two yellow marbles = 5/26