$~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 6-3^{\frac{2}{5}}\implies 6-\sqrt[5]{3^2}\implies 6-\sqrt[5]{9}~~\approx ~~4.8$

3 0

3 years ago

A 13-inch candle is lit and steadily burns until it is burned out.

brilliants [131]

Answer:

a. The remaining length of the candle varies from 10 inches to 5.5 inches

b. Remaining Length = 13 - b

Step-by-step explanation:

The remaining (unburnt) length of the candle must be equal to the difference between total length of the candle and the burnt length of the candle. So, the expression for the remaining length can be written as:

Remaining Length = Total Length - Burnt Length

where,

Total length = 13 inch

Burnt Length = b

Therefore,

Remaining Length = 13 - b

Now, we use the same expression for:

burned length = 3 inches

Therefore,

Remaining Length = 13 inches - 3 inches

Remaining Length = 10 inches

Now, for

burned length = 7.5 inches

Therefore,

Remaining Length = 13 inches - 7.5 inches

Remaining Length = 5.5 inches

Hence,

The remaining length of the candle varies from 10 inches to 5.5 inches

4 0

3 years ago