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2 years ago

BRAINLEST☻

Mathematics

1 answer:

Galina-37 [17]2 years ago

7 0

The answer for your question is the equal sign

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NO BOTS!! What’s The Answer of this math image?

Aleonysh [2.5K]

Answer:

In part B the answer is 71.

Step-by-step explanation:

In the 3 lines the 2 uppermost and downer most lines look like they make up a 90 degree angle.. since the first one is 19 all we have to do is 90 - 19 which equals 71. Sorry I do not know the answer to part A :(

6 0

2 years ago

If yo are given PNM = MOP How would you prove that MNPQ is a parallelogram?

Fed [463]

Answer:

Response 1

Step-by-step explanation:

Response 1 is the only wording that is self-consistent. Response 1 is the appropriate response.

___

Response 2 argues about angles, then concludes sides are congruent. This makes no sense.

Response 3 identifies congruent segments, but they are not opposite sides. The conclusion is unsupported.

4 0

3 years ago

Triangle ABC was dilated by 50%. What is the relationship between AC and A'C'?

Elina [12.6K]

Answer:

The length of segment AC is two times the length of segment A'C'

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

z ----> the scale factor

A'C' ----> the length of segment A'C'

AC ----> the length of segment AC

$z=\frac{A'C'}{AC}$

we have that

$z=50\%=50/100=\frac{1}{2}$ ---> the dilation is a reduction, because the scale factor is less than 1 and greater than zero

substitute

$\frac{1}{2}=\frac{A'C'}{AC}$

$AC=2A'C'$

therefore

The length of segment AC is two times the length of segment A'C'

5 0

2 years ago

Read 2 more answers

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

2 years ago

Read 2 more answers

What’s the expression 4m - 17 + 3m - 11

Rina8888 [55]

=4m - 17+ 3m - 11
combine like terms
=(4m + 3m) + (-17 - 11)
=7m - 28

This can be factored/simplified by dividing everything by 7
=7(m - 4)

Hope this helps! :)

6 0

2 years ago