Answer:
40
Step-by-step explanation:
(2x+1/(2x))^5 *(2x -1/(2x))^5
= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2
= (4x^2-1/4(x)^2)^5
now
x =4x^2. ,a = 1/4(x)^2 ,n =5
we have
general term = Cr *x^r *a^(n-r)
= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)
= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)
= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)
= Cr * 4(2r-n) *x(4r-2n)
now for x^2
4r-2n = 2
4r -10=2
4r =12
r = 3
now for coeff
C(5,3) * 4^(2*3-5)
5!/(3!*(5-3)!) * 4
5*4/(2*1)*4
40
The question is incomplete as the cost price isn't given. However, taking the cost price as x :
Answer:
Kindly check explanation
Step-by-step explanation:
Given :
A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.
Let :
Cost price when new = x
Cost price when sold = 4/5 * cost price when new
Cost when sold = 4/5 of x = 4x/5
Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)
Hence,
Amount of money lost on the car = (x - 4x/5)
x - 4x/5 = (5x - 4x) / 5 = x / 5
To obtain the exact price, kindly input the omitted cost when new for x.
Answer:
y= -6
Step-by-step explanation:
-9y+6=-10y
+10y. +10y
y+6=0
-6. -6
y=-6
Multiply both sides
8x-96=3x+24
move the terms
8x-3x=24+96
collect like terms
5x=120
solution:
x=24
