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2 years ago

What Percent of 25 is 10 ?

Mathematics

2 answers:

Sergio039 [100]2 years ago

4 0

Answer:

Step-by-step explanation:

Vlad [161]2 years ago

3 0

Answer:

40% (see below)

Step-by-step explanation:

First, make a ratio to simplify your situation:

Think about it like this:

If 25 is 100%, and the question is asking me for 10, which is x%, then what is x%?

Here's what I'm talking about:

10 x%

------ = --------

25 100%

Now, just cross multiply and simplify:

1000 = 25x

40 = x

x = 40

To check your answer, you can multiply 25 by 0.4 (the decimal form of 40%) to see if it worked because 40% of 25 is 10:

25 (0.4)

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sergejj [24]

Answer:

(C)c= $\frac{3}{7}$ f

Step-by-step explanation:

Clare uses $9\frac{1}{3}$ cups of flour to make 4 cakes.

It means she uses 1 cup of flour to make $4\div9\frac{1}{3}$ cakes.

Let us simplify that expression first for future use.

$4\div9\frac{1}{3}=4\div\frac{28}{3} =4 X \frac{3}{28} =\frac{3}{7}$

Therefore, Clare uses 1 cup of flour to make $\frac{3}{7}$ cakes.

If Noah follows the same recipe,

He uses f cups of flour to make c cakes

Using Ratio Method

→ Name : Cup : Cake

→ Clare : 1 : $\frac{3}{7}$

→ Noah : f : c

By using cross multiplication

c X 1 = $\frac{3}{7}$ f

c= $\frac{3}{7}$ f

The equation c= $\frac{3}{7}$ f represents the relationship between c and f

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3 years ago

The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?

svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

$V(t) = V(0)(1-r)^{t}$

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that $r = 0.16$

$V(t) = V(0)(1-r)^{t}$

$V(t) = V(0)(1-0.16)^{t}$

$V(t) = V(0)(0.84)^{t}$

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

$V(t) = V(0)(0.84)^{t}$

$0.5V(0) = V(0)(0.84)^{t}$

$(0.84)^{t} = 0.5$

$\log{(0.84)^{t}} = \log{0.5}$

$t\log{0.84} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.84}}$

$t = 3.98$

The half life of the car is 3.98 years.

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