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anyanavicka [17]
2 years ago
8

According to the graph, what is the experimental probability of selecting the letter C?

Mathematics
2 answers:
damaskus [11]2 years ago
7 0

Answer:

The Answer is 0.16 = 16%

Zielflug [23.3K]2 years ago
4 0

Answer:

16%

Step-by-step explanation:

50 events and C shows 8

50/8 = 16%

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Susan tossed a die 996 times. which of the following would be a good estimate of the number of times she got the number 3 on the
nignag [31]

Answer:

i believe the answer is 332

Step-by-step explanation:

basically what i did was divide 3 and 996. when you do that it will let you know the estimate number of the number times she  got number 3 on the die.

5 0
3 years ago
What is the square root of 348
horrorfan [7]
When u keep dividing and dont get it go up by each number and keep divind by every number until u get it which would be
4 0
3 years ago
Solve for x.<br><br> x3=125<br><br> Enter your answer in the box.<br><br> x =
olchik [2.2K]

Answer:

x = 5

Step-by-step explanation:

 =(-5-√-75)/2=(-5-5i√ 3 )/2= -2.5000-4.3301i

x =(-5+√-75)/2=(-5+5i√ 3 )/2= -2.5000+4.3301i

x = 5

source tiger-algebra.com

4 0
3 years ago
Read 2 more answers
At Charles Walters Middle School, 25% of the students live more than 8 miles from school, What fraction of the students live mor
Vanyuwa [196]

Answer:

1/4

Step-by-step explanation:

0.25 = 1/4

8 0
2 years ago
Read 2 more answers
In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a
nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ};

\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ};

\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q.

Also,

\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P in right triangle PBM.

Thus \rm \angle{P\hat{B}M} = \angle C\hat{M}Q.

Additionally \rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}.

Therefore \rm \triangle PBM \sim \triangle MCQ.

\rm \displaystyle BC = 2\;MC for M is the midpoint of segment BC.

\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC.

\rm \triangle PBM \sim \triangle MCQ implies that

\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3.

8 0
3 years ago
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